It would have to be the right type of metal like copper to run through it
Answer: ??? D? dont quote me on it tho <3
Explanation:
To solve this problem we will apply the concepts related to the electric field, linear charge density and electrostatic force.
The electric field is

Here,
= Linear charge density
= Permittivity of free space
r = Distance
The linear charge density can be written as,
Linear charge density is given as

Replacing,


The initial and final electric Force can be written as function of the charge and the electric field as


If we replace the value for the electric field we have,

Length is one third at the end, then

The ratio of the force is


Therefore the required ratio is 3
Answer:
Explanation:
Number of turns
N = 210turns
Length of solenoid
l = 0.18m
Cross sectional area
A = 4cm² = 4 × 10^-4m²
A. Inductance L?
Inductance can be determined using
L = N²μA/l
Where
μ is a constant of permeability of the core
μ = 4π × 10^-7 Tm/A
A is cross sectional area
l is length of coil
L is inductance
Therefore
L = N²μA / l
L=210² × 4π × 10^-7 × 4 × 10^-4 / 0.18
L = 1.23 × 10^-4 H
L = 0.123 mH
B. Self induce EMF ε?
EMF is given as
ε = -Ldi/dt
Since rate of decrease of current is 120 A/s
Then, di/dt = —120A/s, since the current is decreasing
Then,
ε = -Ldi/dt
ε = - 1.23 × 10^-4 × -120
ε = 0.01478 V
ε ≈ 0.015 V
I dotn know sorryyyyyyyyyyy