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Vlad1618 [11]
3 years ago
11

Dr. Eriksson is working on a material called selenium. She is adding a certain number and type of atoms to the selenium, which w

ill control its conductivity.
Selenium is most likely what kind of material?
semiconductor

conductor

superconductor

insulator
Physics
2 answers:
marysya [2.9K]3 years ago
4 0

Semiconductor should be the correct answer!

MaRussiya [10]3 years ago
3 0
Selenium is most likely A SEMI CONDUCTOR. The correct option is A. Substances which are semi conductors are able to conduct electricity to a limited extent. Their conductivity ability can be improved by adding other types of element or material to them.
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How is energy transferred between two objects at different temperatures?
mojhsa [17]

When calculated energy transferred between objects use the definition of heat as

4 0
3 years ago
The electron dot diagram shows the arrangement of dots without identifying the element.
olasank [31]

<em>Answer: </em>tellurium (Te)

<em>atomic number = 52 ,</em>

<em>Number of energy levels = 5;</em>

              First energy level = 2

         Second energy level = 8

             Third energy level = 18

           Fourth energy level = 18

               Fifth energy level = 6

<em>In this electron configuration, 0uter most electrons are 6.</em>


5 0
3 years ago
Read 2 more answers
Enter your answer in the provided box. The mathematical equation for studying the photoelectric effect is hν = W + 1 2 meu2 wher
siniylev [52]

Answer:

v = 4.44 \times 10^5 m/s

Explanation:

By Einstein's Equation of photoelectric effect we know that

h\nu = W + \frac{1}{2}mv^2

here we know that

h\nu = energy of the photons incident on the metal

W = minimum energy required to remove photons from metal

\frac{1}{2}mv^2 = kinetic energy of the electrons ejected out of the plate

now we know that it requires 351 nm wavelength of photons to just eject out the electrons

so we can say

W = \frac{hc}{351 nm}

here we know that

hc = 1242 eV-nm

now we have

W = \frac{1242}{351} = 3.54 eV

now by energy equation above when photon of 303 nm incident on the surface

\frac{1242 eV-nm}{303 nm} = 3.54 eV + \frac{1}{2}(9.1 \times 10^{-31})v^2

4.1 eV = 3.54 eV + (4.55 \times 10^{-31}) v^2

(4.1 - 3.54)\times 1.6 \times 10^{-19}) = (4.55 \times 10^{-31}) v^2

8.96 \times 10^{-20} = (4.55 \times 10^{-31}) v^2

v = 4.44 \times 10^5 m/s

6 0
3 years ago
An electric heater is operated by applying a potential difference of 78.0 V across a nichrome wire of total resistance 7.00 Ω. a
aleksley [76]

PART A)

Here we know that

potential difference across the wire is

V = 78 volts

resistance of wire is

R = 7 ohm

now by ohm's law

V = iR

78 = i(7 ohm)

i = 11.14 A

Part b)

Power rating is defined as rate of electrical energy

it is defined as

P = iV

now we have

P = 11.14 ( 78)

P = 869.1 Watt

8 0
3 years ago
Find the net force for <br> 10 N<br> 10 N<br> 25degree<br> 5N<br> 5N
icang [17]

Answer:

30n

Explanation:

7 0
3 years ago
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