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8_murik_8 [283]

2 years ago

14

A fox, a coyote, and a wolf weigh a total of 120 pounds. The ratio of the weight of the fox to the weight of the coyote is 3:8.

The weight of the coyote is 32 pounds. What is the weight of the wolf?

1 answer:

densk [106]2 years ago

4 0

<span>You haven't given enough information. The best I can say is that the wolf weighs 50 pounds, but I don't think that is right..</span>

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49 leaves

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7 days x 7 leaves per day = 49 leaves in total

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A series of three? separate, adjacent tunnels is constructed through a mountain. Its length is approximately 25 kilometers. Each

Nadya [2.5K]

Answer:

$312.5\pi \text{ km}^3\approx 981.75\text{ km}^3$

Step-by-step explanation:

We have been given that a series of 3 separate, adjacent tunnels is constructed through a mountain. Its length is approximately 25 kilometers.

Each of the three tunnels is shaped like a half-cylinder with a radius of 5 meters.

Since we know that volume of a semicircular or a half cylinder is half the volume of a circular cylinder.

$\text{Volume of a semicircular cylinder}=\frac{\pi r^2h}{2}$ , where,

r = Radius of cylinder,

h = height of the cylinder.

Upon substituting our given values in volume formula we will get,

$\text{Volume of a semicircular cylinder}=\frac{\pi (5\text{ km})^2*25\text{ km}}{2}$

$\text{Volume of a semicircular cylinder}=\frac{\pi*25\text{ km}^2*25\text{ km}}{2}$

$\text{Volume of a semicircular cylinder}=\frac{\pi*625\text{ km}^3}{2}$

$\text{Volume of a semicircular cylinder}=\pi*312.5\text{ km}^3$

$\text{Volume of a semicircular cylinder}=\pi*312.5\text{ km}^3$

$\text{Volume of a semicircular cylinder}=981.74770\text{ km}^3$

Therefore, the volume of earth removed to build the three tunnels is $312.5\pi \text{ km}^3\approx 981.75\text{ km}^3$ .

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2 years ago

10 A solid metallic cylinder of radius 14 cm and

vodomira [7]

Answer:

72 spheres are formed

Step-by-step explanation:

We start by calculating the volume of the metallic cylinder

Mathematically, we have this as;

V = pi * r^2 * h

V = pi * 21 * 14^2

V = 4116 π cm^3

The volume of each small sphere is;

V = 4/3 * pi * r^3

= 4/3 * π * 7/2^3 = 57.167 π cm^3

To get the number of small spheres, we simply divide the volumes

That will be 4116 pi / 57.167 pi = 72

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