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Marta_Voda [28]
3 years ago
14

Please help someone anyone please help

Mathematics
2 answers:
Brrunno [24]3 years ago
8 0

Answer:

if 135 calories represents 1/4 then a whole cup is 540 calories so two cups is 540 times 2 which is 1080

Step-by-step explanation:

ikadub [295]3 years ago
6 0

Answer:

1080 calories

Step-by-step explanation:

135x8=1080

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A limited-edition poster increases in value each year. After 1 year, the poster is worth $20.70. After 2 years, it is worth $23.
kumpel [21]
Assuming that this is a linear relationship you must find the rate of change...$23.81-$20.70= $3.11. 3.11 is how much it changed that year. What that also gives you is how much you bought the post for at 0 years by subtracting $20.70 and the $3.11 = the price of the poster. This gives us the equation y=3.11(x)+17.59
Where Y is the value and X is the amount of years.
3 0
3 years ago
F the sphere shown above has a radius of 5 units, then what is the approximate volume of the sphere?
bogdanovich [222]
<h3>Given:</h3>
  • Radius= 5 units
<h3>To find:</h3>
  • The approximate volume of the given sphere.
<h3>Solution:</h3>

\large\boxed{Formula:V= \frac{4}{3}\pi{r}^{3}}

Let's substitute the values according to the formula.

Let's solve!

V=\frac{4}{3}×\pi×{5}^{3}

V=523.59878 \: {units}^{3}

Now, well have to round off to the nearest hundredth.

\boxed{V=523.6 \: {units}^{3}}

<u>Hence,</u><u> </u><u>the</u><u> </u><u>volume</u><u> </u><u>of</u><u> </u><u>the</u><u> </u><u>given</u><u> </u><u>sphere</u><u> </u><u>is</u><u> </u><u>523.6</u><u> </u><u>cubic</u><u> </u><u>units</u><u>.</u>

Note: If your using π as π you'll get this answer.

3 0
2 years ago
Two gyms offer different rates for taking Cross Fit classes. Muscles Gym charges $4 per
Sedaia [141]

Answer:

69

Step-by-step explanation:

3 0
4 years ago
Estion 4
Sunny_sXe [5.5K]

Answer:

Check Explanation

Step-by-step explanation:

Sale price = GHS80 per unit from first week of December to first week of January.

And at a reduced price of 30% from second week of January to the last week of January.

So, sales price for the second period = 70% × 80 = GHS56

To now find the profits for each of the purchase alternatives, we need to calculate the expected total demand

Expected demand units = (Demand × Probability)

First Period

Demand Probability | Expected demand units

500 0.1 | 50

600 0.3 | 180

750 0.4 | 300

850 0.2 | 170

Second period

Demand Probability | Expected demand units

320 0.5 | 160

180 0.3 | 54

130 0.2 | 26

Total expected demand units for first period = 50 + 180 + 300 + 170 = 700

Total expected demand units for second period = 160 + 54 + 26 = 240

i) When a pack of 600 products only is ordered, it is evident that it will cater for only the first period.

Expected Profit = (Expected sales it can cater for) - (Price of one pack of 600 products)

Expected sales it can cater for = 600 × 80 = GHS 48,000

Expected price of one pack of 600 products = 600 × 60 = GHS 36,000

Expected profit = 48000 - 36000 = GHS 12,000

ii) When a pack of 800 products only is ordered, it is evident that it will cater for the entire first period (700) and 100 from the second period.

Expected Profit = (Expected sales it can cater for) - (Price of one pack of 800 products)

Expected sales it can cater for = (700 × 80) + (100 × 56) = 56,000 + 5,600 = GHS 61,600

Expected price of one pack of 800 products = 800 × 57 = GHS 45,600

Expected profit = 61600 - 45600 = GHS 16,000

iii) When a pack of 1000 products only is ordered, it is evident that it will cater for the entire period, 700 and 240.

Expected Profit = (Expected sales it can cater for) - (Price of one pack of 1000 products)

Expected sales it can cater for = (700 × 80) + (240 × 56) = 56,000 + 13,440 = GHS 69,440

Expected price of one pack of 100 products = 1000 × 52 = GHS 52,000

Expected profit = 69440 - 52000 = GHS 17,440

iv) To do this, we first assume that

- the probabilities provided are very correct.

- the products are sold on a first come first serve basis

- the profits per unit for each period is calculated too.

Profit per product in this case = (16000/800) = GHS 20

For the first period

Expected profit = (700 × 80) - (700 × 57) = GHS 16,100

Average profit per unit = (16100/700) = GHS 23

For the second period

Expected profit = (100 × 56) - (100 × 57) = - GHS 100

Average profit per unit = (-100/100) = -GHS 1

Standard deviation = √[Σ(x - xbar)²/N]

Σ(x - xbar)² = [700 × (23-20)²] + [100 × (-1-20)²]

= 6300 + 44,100 = 50,400

N = 800

Standard deviation per unit = √(50400/800) = GHS 7.94

Variance per unit = (standard deviation per unit)² = (7.94)² = 63.

Variance on 800 units = 800 (1² × 63) = 800 × 63 = 50,400

Standard deviation on profits of 800 units = √(50400) = GHS 224.5

v) With the same assumptions as in (iv), but now, we include the Profit (or more appropriately, the loss from unsold units of products)

Profit per product in this case = (17440/1000) = GHS 17.44

For the first period

Expected profit = (700 × 80) - (700 × 52) = GHS 19,600

Average profit per unit = (19600/700) = GHS 28

For the second period

Expected profit = (240 × 56) - (240 × 52) = - GHS 960

Average profit per unit = (960/240) = GHS 4

The expected unsold products = 1000 - 940 = 60

Profit on those unsold products = 0 - (60 × 52) = -GHS 3,120

Profit per unit = (-3120/60) = - GHS 52

Standard deviation = √[Σ(x - xbar)²/N]

Σ(x - xbar)² = [700 × (28-17.44)²] + [240 × (4-17.44)²] + [60 × (-52-17.44)²]

= 78,059.52 + 43,352.064 + 289,314.816 = 410,726.4

N = 1000

Standard deviation per unit = √(410,726.4/1000) = GHS 20.27

Variance per unit = (standard deviation per unit)² = (20.27)² = 410.7264

Variance on 1000 units = 1000 (1² × 410.7264) = 800 × 410.7264 = 410,726.4

Standard deviation on profits of 1000 units = √(410,726.4) = GHS 640.88

vi) The standard deviation on profits show how much the real profits can range below or abobe the expected profit. That is, the standard deviation basically represents how big the risks or rewards can get.

A larger standard deviation will indicate a higher risk in case of loss and a higher reward in case of profits.

The option with the lower risk is the option with the lower standard deviation.

Hence, a pack of 800 products should be ordered instead of a pack of 1000 products as it has a lower standard deviation and hence, a lower risk attached to it thereby minimizing the risk.

Hope this Helps!!!

5 0
4 years ago
Tonya plans to join a fitness club. She researched the costs to join different clubs in her area and found that there is a linea
Ne4ueva [31]

Answer: 1 club - Club 2

Step-by-step explanation:

You can find the monthly rates by deducting the cost at 12 months from the cost at 24 months and dividing it by 12.

Club 1                                         Club 2                                 Club 3

= (432 - 216) / 12                       = (390 - 210) / 12                 = (504 - 252) / 12

= $18                                          = $15                                   = $21

Multiply these rates by 6 months and any club total cost at 6 month that differs from your answer has a joining fee.

Club 1;                                          Club 2;                                 Club 3

= 18 * 6                                         = 15 * 6                                = 21 * 6

= $108                                          = $90                                  = $126

<em>Same as total cost at              </em><u><em> Joining fee of $30</em></u><em>;      </em>         <em>No joining fee as </em>

<em>6 months so no joining            120 - 90 = $30                      this is the same </em>

<em>fee.                                                                                           as total cost at 6 </em>

<em>                                                                                                 months.</em>

5 0
3 years ago
Read 2 more answers
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