<span>7 × (–3) × (–2)^2
= </span>-21 × 4
= - 84
Hope it helps
Here is all the work with it
Answer:
809 km²
Step-by-step explanation:
I can split this into 3 rectangles. One is 25 by 17, another is 24 by 13, and the last one is 6 by 12. (I had gotten 13 for the second rectangle because 25 - 12 = 13.)
(25 * 17) + (24 * 13) + (6 * 12) <em>{17 is the first number after a multiple of 4 (16). As a result, 25 by 17 will end in "25." 25 by 17 is 425.}</em>
425 + (24 * 13) + (6 * 12) <em>{24 by 13 is 312.}</em>
425 + 312 + (6 * 12) <em>{6 by 12 is 72.}</em>
425 + 312 + 72 <em>{From left to right, add 425, 312, and 72 to get 809}</em>
737 + 72
809 km²
The area of this figure is 809 km².
Answer:
The answer is C. 546.
If a population decreases by 11%, that means that 89% (100% - 11% = 89%) of cheetahs remains each number. 89% can be expressed as 0.89, so to calculate the change of the population, we must each year multiply the number of cheetahs by 0.89.
After 1 year: 1750 * 0.89 ≈ 1558
After 2 years: 1558 * 0.89 ≈ 1387
After 3 years: 1387 * 0.89 ≈ 1234
After 4 years: 1234 * 0.89 ≈ 1098
After 5 years: 1098 * 0.89 ≈ 977
After 6 years: 977 * 0.89 ≈ 870
After 7 years: 870 * 0.89 ≈ 774
After 8 years: 774 * 0.89 ≈ 689
After 9 years: 689 * 0.89 ≈ 613
After 10 years: 613 * 0.89 ≈ 546
Step-by-step explanation:
Mean, x_bar = 1518
Standard deviation, sigma = 325
Range required: 1550 ≤ X ≤ 1575
Z = (X - x_bar)/sigma
Z1 = (1550-1518)/325 ≈ 0.1
Z2 = (1575-1518)/325 ≈ 0.18
From Z tables,
P(Z1) = 0.5398
P(Z2) = 0.5714
P(1550≤X≤1575) = P(Z2) - P(Z1) = 0.5714 - 0.5398 = 0.0316
The correct answer is C.
