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Dimas [21]
3 years ago
9

Dorsey Company manufactures three products from a common input in a joint processing operation. Joint processing costs up to the

split-off point total $335,000 per quarter. For financial reporting purposes, the company allocates these costs to the joint products on the basis of their relative sales value at the split-off point. Unit selling prices and total output at the split-off point are as follows:
Product Selling Price Quarterly Output
A $17.00 per pound 12,400 pounds
B $11.00 per pound 19,400 pounds
C $23.00 per gallon 3,600 gallons

Each product can be processed further after the split-off point. Additional processing requires no special facilities. The additional processing costs (per quarter) and unit selling prices after further processing are given below:

Product Additional Processing Costs Selling Price
A $63,720 $21.80 per pound
B $91,120 $16.80 per pound
C $37,360 $30.80 per gallon

Required:
a. What is the financial advantage (disadvantage) of further processing each of the three products beyond the split-off point?
b. Based on your analysis in requirement 1, which product or products should be sold at the split-off point and which product or products should be processed further?
c. What is the financial advantage (disadvantage) of further processing each of the three products beyond the split-off point?
Business
1 answer:
g100num [7]3 years ago
8 0
Have no clue sorry that is not the answer
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April runs a small shop where she provides a service. She is able to process an average of 11 customers per hour. An average of
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Answer:

5. Po= 0.36

6. Pn = 0.04

7. 0.16

8. 1.11

9. 1.75

10. 9.9

Explanation:

5. Computation for the probability that April will not be working with a customer

Using this formula

Po=1-(Average number of arrival per hour/Average number of customer served per hour)

Let plug in the formula

Po= 1-(7/11 )

Po=1-0.64

Po= 0.36

Therefore the probability that April will not be working with a customer will be 0.36

6. Calculation for the probability of 5 customers in the system

Using this formula

Pn= (Average number of arrival per hour/Average number of customer served per hour)* Po

Let plug in the formula

Pn= (7/11)^5* 0.36

Pn=0.104358*0.36

Pn=0.037

Pn = 0.04 (Approximately)

Therefore the probability of 5 customers in the system will be 0.04

7. Calculation for the average time a customer spends waiting in line

Time spend Waiting in line=7^2/11(11 – 7) /7

Time spend Waiting in line=(49/44)/7

Time spend Waiting in line = 1.11/7

Time spend Waiting in line= 0.16

Therefore the average time a customer spends waiting in line will be 0.16

8. Calculation for the average number of customers waiting in line

Customers waiting in line = 7^2/11(11 – 7)

Customers waiting in line=49/44

Customers waiting in line= 1.11

Therefore the average number of customers waiting in line will be 1.11

9. Calculation for the average number of customers in the system

Average customers in the system= 1.11 +(7/11)

Average customers in the system= 1.11 +0.64

Average customers in the system = 1.75

Therefore the average number of customers in the system will be 1.75

10. Calculation for the arrival rate in order for April to stay that busy

Arrival rate = 0.9 * 11

Arrival rate = 9.9

Therefore the arrival rate in order for April to stay that busy will be 9.9

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