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Tcecarenko [31]
4 years ago
6

What how many degrees variation is there between the highest temperatures and lowest temperatures on the moon? about 550ºC about

180ºC about 130ºC about 310ºC
Chemistry
1 answer:
kirill [66]4 years ago
7 0

Answer:

about 310ºC

Explanation:

The Moon is the natural satellite of the Earth.

The Moon orbits around the Earth in approximately 27 days, and its average distance from the Earth is about 380,000 km.

Moreover, the mass of the Moon is 7.35\cdot 10^{22}kg.

The Moon has no water on its surface and no atmosphere: due to the lack of atmosphere, heat coming from Solar radiation is not retained near the surface. Moreover, the Moon orbits around the Earth keeping one face always towards it, so every location on the Moon has 13 consecutive days of daylight followed by 13 days of darkness.

As a result, there is a large thermic excursion between the maximum and minimum temperature on the Moon. In particular, we have:

- Minimum temperature: -173 degrees Celsius

- Maximum temperature: +127 degrees Celsius

So this difference is about

\Delta T = 127-(-173)=300^{\circ}C

So, about 310ºC.

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Answer:

Constraints are restrictions that need to be placed upon variables 

Explanation:

Constraints are restrictions (limitations, boundaries) that need to be placed upon variables used in equations that model real-world situations. It is possible that certain solutions which make an equation true mathematically, may not make any sense in the context of a real-world word problem.

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3 years ago
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Answer:

mNaNO3 =765g

Explanation:

First, we write the balanced chemical equation representing the chemical reaction that happened between aluminum nitrate and sodium chloride.

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AL(NO3)3+3NaCl ⟶ 3 NaNO3+AlCl3

According to the equation, each mole of aluminum nitrate requires three moles of sodium chloride. Thus, the required number of moles of sodium chloride is

4 Mol ⋅ 3 = 12mol

Based on the data provided in the table, there were 9 moles of sodium chloride used in the reaction, which was not enough for the entirety of aluminum nitrate to react. So, sodium chloride must have been the limiting reactant.

Therefore, we use the number of moles (n) of sodium chloride to calculate the number of moles of sodium nitrate, which has a 1:1 ratio with sodium chloride.

Number of moles sodium nitrate:

nNaNO3=nNaCl

nNaNO3 = 9 mol

We can also calculate the mass (m) of sodium nitrate that was produced by multiplying its number of moles by its molar mass (MM), 85.00g/mol.

Mass of sodium nitrate produced:

mNaNO3 = nNaNO3 ⋅ MMNaNO3

mNaNO3 = 9 mol ⋅ 85.00 g/mol

mNaNO3 =765g

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