Answer:
Tin (IV) sulfide and antimony (III) sulfide be separated from copper (II) sulfide and bismuth (III) sulfide by the addition of sodium hydroxide because they become soluble whereas copper (II) sulfide and bismuth (III) sulfide remain insoluble.
Explanation:
Sodium hydroxide is a basic solution which is used as a precipitating agent for metallic ions in the laboratory.
<em>When a solution containing a mixture of the sulfides of the Group II cations, antimony (III), copper (II), tin (IV), and bismuth (III), is made basic by the addition of a base such as sodium hydroxide or ammonium hydroxide, the sulfide ion concentration will increase. The sulfides of antimony (III) and tin (IV) will then become soluble because antimony (III) and tin (IV) form stable complexes with sulfide, which are soluble in water, while the sulfides of copper (II) and bismuth (III) do not.</em> The result is the dissolution of the antimony (III) sulfide and tin (IV) sulfide, separating them from the copper (II) sulfide and the bismuth (III) sulfide.
Sb₂S₃(s) + 3S²⁻(aq) ----> 2SbS₃³⁻(aq)
SnS₂(s) + S²⁻(aq) ----> SnS₃³⁻(aq)
Answer:
1. Diagram C.
2. Diagram A.
Explanation:
1. Calcium atom, Ca has 20 protons and 20 electrons. On the other hand, Calcium ion, Ca^2+ has 20 protons and 18 electrons. This is true because the +2 charge on the calcium ion, Ca^2+ indicates that the calcium atom, Ca has loss 2 electrons.
From the above illustration we can say that calcium ion, Ca^2+ has the following:
Proton = 20
Electron = 18
Therefore, diagram C indicates calcium ion, Ca^2+.
2. Fluorine atom, F has 9 protons and 9 electrons. Fluoride ion, F¯ has 9 protons and 10 electrons. This is so because the –1 charge on the fluoride ion, F¯ indicates that the fluorine atom, F has gained 1 electron.
Thus, we can say that the fluoride ion, F¯ has the following:
Proton = 9
Electron = 10
Therefore, diagram A represent fluoride ion, F¯.
Answer:
The law of conservation of matter states that in a chemical reaction matter cannot be created or destroyed
Explanation:
