Answer:
activation energy hope this is right
V = 28,42 mL = 0,02 L
molar mass C3H6O = 58
n C3H6O
= V / 22,4
= 0,02 / 22,4
= 0,0009 mol
mass
= n x molar mass
= 0,0009 x 58
= 0,0522 gr
Answer:
X(EtOH) = 0.0891
X(H₂O) = 0.9109
Explanation:
Given 20% aqueous solution ethanol.
Ethanol => C₂H₅OH (or, EtOH) => molecular weight = 46 g//mole
20% solution by weight = 20 grams EtOH / 100 grams of solution
20 grams EtOH / 100 grams of solution = 20 grams EtOH + 80 grams H₂O
moles EtOH = (20g/46g/mol) = 0.4348 mole
moles H₂O = (80g/18g/mol) = 4.4444 mole
moles EtOH + moles H₂O = 0.4348 + 4.4444 = 4.8792
X(EtOH) = 0.4348/4.8792 = 0.0891
X(H₂O) = 4.4444/4.8792 = 0.9109
∑mole fractions must equal 1.000 => 0.0891 + 0.9109 = 1.000 (check!)
Answer:
option D
Explanation:
Given,
V₁ = 285 L
P₁ = 530 mm Hg
Standard pressure
P₂ = 760 mm Hg
V₂ = ?
Using relation between pressure and volume
Hence, volume of the propane at standard pressure is equal to 198.8 L.
Hence, the correct answer is option D.
