3 years ago

Calculate the ph of a solution in which [oh–] = 4.5 × 10–9m.

Chemistry

1 answer:

frosja888 [35]3 years ago

5 0

pOH = -LOG([OH])

pOH = -LOG(4.5*10^-9)

pOH = 8.34

pH + pOH = 14

pH = 14 - 8.34 = 5.65

hope this helps!

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