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marin [14]
3 years ago
8

Calculate the ph of a solution in which [oh–] = 4.5 × 10–9m.

Chemistry
1 answer:
frosja888 [35]3 years ago
5 0

pOH = -LOG([OH])  

pOH = -LOG(4.5*10^-9)  

pOH = 8.34  

pH + pOH = 14  

pH = 14 - 8.34 = 5.65

hope this helps!

(:

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