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2 years ago

a shark can swim 4 kilometers in 1/10 hours A blue whale can swim 5 kilometers in 1/4 which one is the fasts UNIT RATE

Mathematics

1 answer:

Basile [38]2 years ago

8 0

Answer:

The Shark

Step-by-step explanation:

If a shark can swim 4 kilometers in 1/10 of an hour and a blue whale can swim 5 kilometers in 1/4 of an hour then we can multiply 5 kilometers by 4 and 4 kilometers by 5 then we get both of them have travled 20 kilometers. Then we multiply 1/10 by 5 and 1/4 by 4 and we get that the shark travled 20 kilometers in 5/10 of an hour (or half an hour) and the blue whale travled 20 kilometers in 1 1/4 of an hour (or 1 hour and 15 minutes)

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Please help!!! I will give brainliest but only if you try and help.

Slav-nsk [51]

Answer:

Since we have to predict, we can use ratios to help us solve this.

12 said yes out of 72 randomly chosen, SO,

if 210 would say yes (goes to play), how many is total??

12 is to 72 AS 210 is to HOW MUCH (let it be x)??

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Rudiy27

Answer:

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3 years ago

Read 2 more answers

Find a and b if the point p(6,0) and Q(3,2) lie on the graph of ax+ by=12

tiny-mole [99]

to get the equation of any straight line we only need two points off of it, hmmm let's use P and Q here and then let's set the equation in standard form, that is

standard form for a linear equation means

• all coefficients must be integers, no fractions

• only the constant on the right-hand-side

• all variables on the left-hand-side, sorted

• "x" must not have a negative coefficient

$(\stackrel{x_1}{6}~,~\stackrel{y_1}{0})\qquad (\stackrel{x_2}{3}~,~\stackrel{y_2}{2}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{2}-\stackrel{y1}{0}}}{\underset{run} {\underset{x_2}{3}-\underset{x_1}{6}}}\implies \cfrac{2}{-3}\implies -\cfrac{2}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{0}=\stackrel{m}{-\cfrac{2}{3}}(x-\stackrel{x_1}{6})$

$\stackrel{\textit{multiplying both sides by }\stackrel{LCD}{3}}{3(y-0)~~ = ~~3\left( -\cfrac{2}{3}(x-6) \right)}\implies 3y=-2(x-6) \\\\\\ 3y=-2x+12 \implies \stackrel{a}{2} x+\stackrel{b}{3} y=12$

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