Answer:
P₂ = 299.11 KPa
Explanation:
Given data:
Initial volume = 600 mL
Initial pressure = 70.00 KPa
Initial temperature = 20 °C (20 +273 = 293 K)
Final temperature = 40°C (40+273 = 313 K)
Final volume = 150.0 mL
Final pressure = ?
Formula:
P₁V₁/T₁ = P₂V₂/T₂
P₁ = Initial pressure
V₁ = Initial volume
T₁ = Initial temperature
P₂ = Final pressure
V₂ = Final volume
T₂ = Final temperature
Solution:
P₂ = P₁V₁ T₂/ T₁ V₂
P₂ = 70 KPa × 600 mL × 313 K / 293K ×150 mL
P₂ = 13146000 KPa .mL. K /43950 K.mL
P₂ = 299.11 KPa
The balanced equation is:
Then proceed with the following equations.
The answer is
.
Answer:
Energy emitted by photon = 45.06 × 10−32 J
Explanation:
Energy of photon is given by E = hf
where
h is the Planck's constant whose value is 6.626×10−34J⋅s
f is the frequency of photon
________________________________________
given that
f = 6.8 x 104 Hz
1 HZ = 1 s^-1
E = 6.626×10−34J⋅s * 6.8 x 10^4 Hz
E = 45.06 × 10−32 J
Thus,
Energy emitted by photon is 45.06 × 10−32 J
Answer:
ig activated complex coz reactants were diaatomic molecules and they were stable initially later on we collided them so they broke into activated complex and they were highly unstable so that they bonded again with another ion!!!! so according to me B is correct OPTION!!
