Question

Can someone please help me? :)

Answer 1

The size of a crowd standing along with a 1/4 mile section of a parade route: 5280 people

Further explanation

Comparison is an effort to compare two or more objects in terms of shape or size, or number

Proportional Comparisons are comparisons of two or more numbers where one number increases, the other numbers also increase

Can be formulated

$\frac{x1}{y1}=\frac{x2}{y2}$

so that if:

x = 2

then

$y=\frac{y}{x}\times\:2$

While the reversal value comparison is the comparison of two or more numbers where one number increases, the other number decreases in value

Can be formulated

$\frac{x1}{y2}=\frac{x2}{y1}$

so that if:

x = 2

then

$y=\frac{x}{y}\times\:2$

The size of a crowd who can see the parade can be calculated using the principle of proportional comparison

• 1. We calculate the ratio of people and areas that can be occupied

The question stated that 10 people occupy a square measuring 5 feet by 5 feet

means the area occupied by 10 people = 5 ft x 5 ft = 25 ft²

so the ratio is :

$\frac{10}{25}$

• 2. We calculate the area of ​​the road that can be occupied when viewing the parade

Because there are 1/4 mile section of a parade route and 5 feet deep on both sides of the street, the total area

1 mile = 5280 ft

1/4 mile = 1320 ft

Total area = 1320 ft x 5 ft (deep) x 2 (both sides of the street) = 13200 ft²

Then the comparison of points 1 and 2 can be used to calculate the total number of people who saw the parade

$\frac{10\:people}{25\:ft^2\:area}=\frac{total\:people\:watched}{13200\:ft^2\:total\:area}$

Total people =

$\frac{10\:\times\:13200}{25}$

Total people = 5280 (C)

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Keywords: parade, street, area, crowd, comparison