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MakcuM [25]
2 years ago
9

The vertex of a parabola is (0,0)and the focus is (1/8, 0) . What is the equation of the parabola?

Mathematics
1 answer:
Aleonysh [2.5K]2 years ago
5 0

The equation of a parabola whose vertex is (0, 0) and focus is (1 / 8, 0) is equal to x = 2 · y².

<h3>How to derive the equation of the parabola from the locations of the vertex and focus</h3>

Herein we have the case of a parabola whose axis of symmetry is parallel to the x-axis. The <em>standard</em> form of the equation of this parabola is shown below:

(x - h) = [1 / (4 · p)] · (y - k)²     (1)

Where:

  • (h, k) - Coordinates of the vertex.
  • p - Distance from the vertex to the focus.

The distance from the vertex to the focus is 1 / 8. If we know that the location of the vertex is (0, 0), then the <em>standard</em> form of the equation of the parabola is:

x = 2 · y²     (1)

The equation of a parabola whose vertex is (0, 0) and focus is (1 / 8, 0) is equal to x = 2 · y².

To learn more on parabolae: brainly.com/question/4074088

#SPJ1

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Answer:

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General Formulas and Concepts:

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Step-by-step explanation:

<u>Step 1: Define</u>

f(x) = x² - 12

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<u>Step 2: Evaluate</u>

  1. Substitute:                   f(5) = 5² - 12
  2. Exponents:                  f(5) = 25 - 12
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\begin{gathered} y=-1-\frac{2}{5}x\Longrightarrow y=-\frac{2}{5}x-1 \\  \\ \text{Now that it is in the slope intercept form} \\ y=-\frac{2}{5}x-1 \\ \text{we can determine that the slope is } \\ m=-\frac{2}{5} \\ \text{and the y-intercept is} \\ b=-1 \end{gathered}

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