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MakcuM [25]
1 year ago
9

The vertex of a parabola is (0,0)and the focus is (1/8, 0) . What is the equation of the parabola?

Mathematics
1 answer:
Aleonysh [2.5K]1 year ago
5 0

The equation of a parabola whose vertex is (0, 0) and focus is (1 / 8, 0) is equal to x = 2 · y².

<h3>How to derive the equation of the parabola from the locations of the vertex and focus</h3>

Herein we have the case of a parabola whose axis of symmetry is parallel to the x-axis. The <em>standard</em> form of the equation of this parabola is shown below:

(x - h) = [1 / (4 · p)] · (y - k)²     (1)

Where:

  • (h, k) - Coordinates of the vertex.
  • p - Distance from the vertex to the focus.

The distance from the vertex to the focus is 1 / 8. If we know that the location of the vertex is (0, 0), then the <em>standard</em> form of the equation of the parabola is:

x = 2 · y²     (1)

The equation of a parabola whose vertex is (0, 0) and focus is (1 / 8, 0) is equal to x = 2 · y².

To learn more on parabolae: brainly.com/question/4074088

#SPJ1

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A company sells a mix of peanuts and cashews. For every 3 ounces of peanuts, there are 2 ounces of cashews. A batch has 60 ounce
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Answer:

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Read 2 more answers
Geometry The length of a rectangle is repfesented by 4a + 3b, and its width is represented by 3a 2b. Write a polynomial for the
Finger [1]
the correct question is
<span>The length of a rectangle is represented by 4a + 3b, and its width is represented by 3a-2b. Write a polynomial for the perimeter of the rectangle. What is the minimum perimeter of the rectangle if a=12 and b is a non-zero </span>whole number?

we know that
Perimeter of a rectangle=2*[length + width]
length=(4a+3b)
width=3a-2b
so
P=2*[(4a+3b)+(3a-2b)]-----> P=2*[7a+b]-----> P=14a+2b

the answer part a) is
A polynomial for the perimeter of the rectangle is P=14a+2b

Part b) 
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P=14*12+2b---------> P=168+2b
<span>the minimum perimeter of the rectangle is for b=1
</span>so
P=168+2*1-----> P=170 units

the answer part b) is 
the minimum perimeter of the rectangle is 170 units


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