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2 years ago

Please HELP!!!!

Mathematics

1 answer:

MA_775_DIABLO [31]2 years ago

3 0

Answer: 184.08 l.y.

Step-by-step explanation:

Let the width of Orion's belt is x light year.

By cosine law,

$(x)^2 = (915)^2+(736)^2-2\times 915\times 736 cos3^{\circ}$

$(x)^2 = 837225+541696-1346880 cos3^{\circ}$

$(x)^2 = 837225+541696-1345034.14777$

$(x)^2 = 33886.8522298$

$x = 184.08381849\approx 184.08$

Thus, the width of the Orion's belt is 184.08 light year.

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2 years ago

PLEASE HELP. I need DE AND EF!!!

AlekseyPX

Answer:

DE = about 41.843 (rounded to nearest thousandth)

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Step-by-step explanation:

For DE, we know that the shorter side (the opposite side) is 24, while the angle across form it is 35°. We can use trigonometry to figure this out. SinФ equals the opposite side (in this case, 24) divided by the hypotenuse. Set sinФ equal to a ratio of the sides like this:

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Answer:

<h2>AAA postulate.</h2>

Step-by-step explanation:

Givens

Angles KOM and LNM are congruent, because both are right.
Angle LNM is common to both triangles.

If two internal angles of two triangles are congruent, then the third angle is also congruent.

Therefore, the similarity is proven by AAA postulate, which states that if we have three corresponding angles congruent, then those triangles are similar.

Remember that similarity is about proportion between sides and congruence between angles.

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