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3 years ago

Please HELP!!!!

Mathematics

1 answer:

MA_775_DIABLO [31]3 years ago

3 0

Answer: 184.08 l.y.

Step-by-step explanation:

Let the width of Orion's belt is x light year.

By cosine law,

$(x)^2 = (915)^2+(736)^2-2\times 915\times 736 cos3^{\circ}$

$(x)^2 = 837225+541696-1346880 cos3^{\circ}$

$(x)^2 = 837225+541696-1345034.14777$

$(x)^2 = 33886.8522298$

$x = 184.08381849\approx 184.08$

Thus, the width of the Orion's belt is 184.08 light year.

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2 years ago

PLEASE HELP. I need DE AND EF!!!

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Answer:

DE = about 41.843 (rounded to nearest thousandth)

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Step-by-step explanation:

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2 years ago

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Answer:

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Step-by-step explanation:

Givens

Angles KOM and LNM are congruent, because both are right.
Angle LNM is common to both triangles.

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Remember that similarity is about proportion between sides and congruence between angles.

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