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EastWind [94]
4 years ago
10

True or False? Changes in temperature, pressure and volume affect the behavior of gases more than they affect solids and liquids

.
Chemistry
1 answer:
Flauer [41]4 years ago
3 0

Answer:

True

Explanation:

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What is required for storing chemicals
AnnZ [28]
A chemical storing thing
4 0
2 years ago
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Which of the following is the composition of an isotope of calcium (atomic number 20)?
ivolga24 [154]

20 protons

20 electrons ( as much elctrons as protons because there has to be same positive and negative to have a neutral atom)

And the number of neutrons depends of the mass number but in that case, I think that it's a Calcium atom (Ca) and so there are 20 netrons.

5 0
3 years ago
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Help pls thnk you!!!!
Degger [83]
The amine here is the easiest to spot since there’s only one structure that has a nitrogen atom, which would be the first (the first structure is a primary amine).

The distinguishing functional group of an alcohol is the hydroxy group (—OH). Both the second and third structures have an —OH group, but the —OH in the third structure is part of a carboxyl group (—COOH or —C(=O)OH). A carboxyl group takes priority over hydroxy group. Thus, the second structure would be an alcohol and the third structure would be a carboxylic acid.

That leaves us with the fourth structure, a hydrocarbon with a halogen substitutent, or, aptly named, a halocarbon.
8 0
3 years ago
How many moles ar Li are in 9.53x^24 atoms of Li?
Anna35 [415]

Answer: 15.83 mol

Explanation:

To convert from atoms to moles, we will need to use Avogadro's number.

Avogardo's number: 6.022×10²³ atoms/mol

9.53*10^{24} atoms*\frac{1mol}{6.022*10^2^3 atoms} =15.83 mol

Now, we know that there are 15.83 moles.

5 0
3 years ago
Two chemicals a and b are combined to form a chemical
dedylja [7]
-dB/dt = kAB = k(2B)(B) = 2kB^2
-dB/B^2 = 2kdt
Integrating: 1/B - 1/(B_0) = 2kt
At t = 10, if 15 g of C have formed, this must have consumed 10 g A and 5 g B. The remaining mass of B is 45 g.
1/45 - 1/50 = 2(k)(10)
k = 1.11 x 10^-4
Then substituting this value of k with t = 40:
1/B - 1/50 = 2(1.11 x 10^-4)(40)
1/B - 1/50 = 0.008889
1/B = 0.028889
B = 34.62 g remaining
Therefore, 50 - 34.62 = 15.38 g of B have been consumed.
Doubling, 30.76 g of A have been consumed.
This means that 15.38 + 30.76 = 46.15 g of C have been formed.
5 0
3 years ago
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