Answer:
MnO₄⁻ + 2 H₂O + 3 e⁻ ⇒ MnO₂ + 4 OH⁻
2 moles of H₂O are on the reactant side.
Explanation:
Let´s consider the following half-reaction.
MnO₄⁻ ⇒ MnO₂
This reduction of permanganate to manganese dioxide happens in a neutral medium. The oxidation number of Mn changes from +7 to +4. When we are in a neutral medium, we can balance the reaction using the ion-electron method either as we were in acid or in basic medium. In this case, to satisfy the condition is the task (<em>water on the reactant side</em>) we will balance this half-reaction as if it were in basic media. Since Mn is already balanced, we have to balance O. We will add as many moles of water as excess of oxygen there is on 1 side, and the double of OH⁻ on the other side. Finally, we add as many electrons as we need to balance it electrically.
MnO₄⁻ + 2 H₂O + 3 e⁻ ⇒ MnO₂ + 4 OH⁻
oh wait i wrote whole paragraphs let me fix this
okay so you mean this ?
a term for disaccharides would be double sugar or boise!
monosaccharides are simple sugars soluble in water. any class of sugars like glucose.
polysaccharide is starch, cellulose, or glycogen. with molecules together. a carbohydrate.
saccharide knows as to the term structure of carbohydrates. carbohydrates are plain simple? organic compounds that are aldehyde or ketone functional group. with the general chemical formula of carbohydrates is c (H O)
n. 2. n
Answer: 5
Explanation: Arsenic, As, has 5 electrons in the 4th energy shell. 4s^2 and 4p^3. The electrons being added for the elements scandium through zinc are all going into the 3d orbital, in the 3rd energy shell. They don't count, since valence electrons are only those in the highest energy level, 4 in this case.
Answer : The mass of the water in two significant figures is, 
Explanation :
In this case the heat given by the hot body is equal to the heat taken by the cold body.
where,
= specific heat of iron metal = 
= specific heat of water = 
= mass of iron metal = 32.3 g
= mass of water = ?
= final temperature of mixture = 
= initial temperature of iron metal = 
= initial temperature of water = 
Now put all the given values in the above formula, we get
Therefore, the mass of the water in two significant figures is,
