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Illusion [34]
3 years ago
5

Distinguish between mass and weight

Chemistry
2 answers:
ziro4ka [17]3 years ago
5 0

Answer:

Mass if the amount of matter in something, while weight is gravity acting on mass.

Explanation:

Mass is the simple measure of the amount of matter in an object, while weight is the force exerted by the object on the area beneath it as a result of gravity or another attractive force.

yKpoI14uk [10]3 years ago
3 0

Answer:

There is a basic difference, because mass is the actual amount of material contained in a body and is measured in kg, gm, etc. Whereas weight is the force exerted by the gravity on that object mg. Note that mass is independent of everything but weight is different on the earth, moon, etc.

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Write a mechanism for the esterification of propanoic acid with 18O-labeled ethanol. Show clearly the fate of the 18O label. (b)
tatuchka [14]

Answer:

See explanation and images attached

Explanation:

a) In the mechanism for the acid catalysed esterification of propanoic acid using ethanol, we can see that the first step is the protonation of the acid followed by nucleophillic attack of the alcohol. Loss of water and consequent deprotonation regenerates the acid catalyst. We can see the fate of the 18O labelled ethanol in the mechanism shown.

b)  In the second mechanism, an unnamed ester is hydrolysed using an acid catalyst. The attack of the acid and subsequent nucleophillic attack of water labelled with 18O leads to the incorporation of this 18O into the product acid as shown in the mechanism attached to this answer.

5 0
3 years ago
if 26.8g of copper (ll) chloride are dissolved in sufficient water to make 4.00 L of solution, what is the molarity of the solut
artcher [175]

Answer: Molarity of the solution is 4.97 \times 10^{-2} M and water is the solvent.

Explanation:

Given: Mass of solute = 26.8 g

Volume = 4.00 L

Now, moles of copper (II) chloride (molar mass = 134.45 g/mol) are calculated as follows.

No. of moles = \frac{mass}{molar mass}\\= \frac{26.8 g}{134.45 g/mol}\\= 0.199 mol

Molarity is the number of moles of a substance divided by volume of solution in liter.

Therefore, molarity of given solution is calculated as follows.

Molarity = \frac{no. of moles}{Volume (in L)}\\= \frac{0.199 mol}{4.00 L}\\= 0.04975 M\\= 4.97 \times 10^{-2} M

Solvent is defined as a component which is present in higher amount in a solution. Generally, a solvent is present in liquid state but it can also be a solid or gas.

In the given solution, copper (II) chloride is dissolved in water so copper (II) chloride is the solute and water is the solvent.

Thus, we can conclude that molarity of the solution is 4.97 \times 10^{-2} M and water is the solvent.

4 0
3 years ago
What phase change is the following substance undergoing?
Dvinal [7]

Answer:

b melting

Explanation:

The phase change the substance is undergoing is from solid to liquid and this is called melting.

  • To understand this process, we need to know the the substance changing.
  • A substance that contains particles that are not easily compressed and packed is a solid.
  • Solids have fixed shapes and volumes.
  • Liquids can easily flow although they cannot also be easily compressed.

The phase change from solid to liquid is facilitated by a melting process.

5 0
3 years ago
Where can most stars
Nesterboy [21]

Answer:

main sequence

Explanation:

The main sequence is a band of stars which includes most of them like our sun

5 0
3 years ago
Read 2 more answers
whats the specific heat of an unknown substance if the addition of 800 joules of heat energy caused a 30 gram sample to warm fro
Troyanec [42]

 The specific heat capacity of unknown  substance  is 1.333 g/j/°c


  <u><em> calculation</em></u>

 Specific heat capacity is calculated using  Q= MCΔT  formula

where;

Q(heat)= 800 j

M(mass) = 30 g

C(specific heat  capacity) =?

ΔT( change in temperature)  = 40°c - 20°c = 20°c

make C  the subject of the formula  by diving both side of the formula by MΔT

C  is therefore = Q/MΔT

800j / 30 g x  20°c = 1.333 j/g/°c

7 0
3 years ago
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