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Illusion [34]
3 years ago
5

Distinguish between mass and weight

Chemistry
2 answers:
ziro4ka [17]3 years ago
5 0

Answer:

Mass if the amount of matter in something, while weight is gravity acting on mass.

Explanation:

Mass is the simple measure of the amount of matter in an object, while weight is the force exerted by the object on the area beneath it as a result of gravity or another attractive force.

yKpoI14uk [10]3 years ago
3 0

Answer:

There is a basic difference, because mass is the actual amount of material contained in a body and is measured in kg, gm, etc. Whereas weight is the force exerted by the gravity on that object mg. Note that mass is independent of everything but weight is different on the earth, moon, etc.

You might be interested in
Hydrazine reacts with oxygen according to the following equation: N2H4(g) +O2(g) → N2(g) + 2 H2O(l) How many L of N2, measured a
mihalych1998 [28]

Answer:

V ≈ 646.50 L

General Formulas and Concepts:

<u>Chemistry - Gas Laws</u>

  • Reading a Periodic Table
  • Stoichiometry
  • Combined Gas Law: PV = nRT
  • R constant - 62.4 (L · torr)/(mol · K)
  • Kelvin Conversion: K = °C + 273.15

Explanation:

<u>Step 1: Define</u>

RxN:   N₂H₄ (g) + O₂ (g) → N₂ (g) + 2H₂O (l)

Given:   34.9 °C, 755.08 torr, 914.894 g H₂O

<u>Step 2: Identify Conversions</u>

Kelvin Conversion

Molar Mass of H - 1.01 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of H₂O - 2(1.01) + 16.00 = 18.02 g/mol

<u>Step 3: Convert</u>

Stoichiometry:   914.894 \ g \ H_2O(\frac{1 \ mol \ H_2O}{18.02 \ g \ H_2O} )(\frac{1 \ mol \ N_2}{2 \ mol \ H_2O} ) = 25.3955 mol N₂

Temperature:    34.9 + 273.15 = 308.05 K

<u>Step 4: Find Volume</u>

  1. Substitute variables:                                                                             (755.08 torr)V = (25.3955 mol)(62.4 (L · torr)/(mol · K))(308.05 K)
  2. Multiply:                                                                                                      (755.08 torr)V = 488160 L · torr
  3. Isolate <em>V</em>:                                                                                                          V = 646.502 L

<u>Step 5: Check</u>

<em>We are given 5 sig figs as our lowest. Follow sig fig rules and round.</em>

646.502 L ≈ 646.50 L

6 0
3 years ago
How many liters of CO2 are in 4.76 moles? (at STP)
dem82 [27]

<u>Answer:</u> The volume of carbon dioxide gas at STP for given amount is 106.624 L

<u>Explanation:</u>

We are given:

Moles of carbon dioxide = 4.76 moles

<u>At STP:</u>

1 mole of a gas occupies a volume of 22.4 Liters

So, for 4.76 moles of carbon dioxide gas will occupy a volume of = \frac{22.4L}{1mol\times 4.76mol=106.624L

Hence, the volume of carbon dioxide gas at STP for given amount is 106.624 L

6 0
3 years ago
How many moles are there in 2.00 x 10^19 molecules of CCl4
HACTEHA [7]

Answer: 0.0000332mol

Explanation: 1mole of CCl4 contains 6.02x10^23 molecules.

Therefore, X mol of CCl4 will contain 2 x 10^19 molecules i.e

Xmol of CCl4 = 2 x 10^19/ 6.02x10^23 = 0.0000332mol

7 0
3 years ago
The solubility of nitrogen gas at 25 ◦C and 1 atm is 6.8×10−4 mol/L. If the partial pressure of nitrogen gas in air is 0.76 atm,
iris [78.8K]

Answer:

Concentration of dissolved nitrogen = 5.2 × 10⁻⁴ mol/L

Explanation:

More the pressure of the gas, more will be its solubility.

So, for two different pressure, the relation between them is shown below as:-

\frac {P_1}{C_1}=\frac {P_2}{C_2}

Given ,  

P₁ = 1 atm

P₂ = 0.76 atm

C₁ = 6.8 × 10⁻⁴ mol/L

C₂ = ?

Using above equation as:

\frac{1\ atm}{6.8\times 10^{-4}\ mol/L}=\frac{0.76\ atm}{C_2}

C_2=\frac{0.76\times 6.8\times 10^{-4}}{1}\ mol/L

<u>Concentration of dissolved nitrogen = 5.2 × 10⁻⁴ mol/L</u>

5 0
3 years ago
Can someone please help me with this question also explain the answers I am so confused thank you.
Archy [21]

The theoretical yield of H₂S is 13.5 g.

The percent yield is 75.5 %.

<h3>What is the theoretical yield of H₂S from the reaction?</h3>

The equation of the reaction is given below:

  • FeS + 2 HCl → FeCl₂+ H₂S

Moles of FeS reacting = mass/molar mass

Molar mass of FeS = 88 g/mol

Moles of FeS reacting = 35/88 = 0.398 moles

Moles of H₂S produced = 0.398 moles

Molar mass of H₂S = 34 g/mol

Mass of H₂S produced = 0.398 * 34 = 13.5 g

Theoretical yield of H₂S is 13.5 g.

  • Percent yield = actual yield/theoretical yield * 100%

Actual yield of H₂S = 10.2 g

Percent yield = 10.2/13.5 * 100%

Percent yield = 75.5 %

In conclusion, the actual yield is less than the theoretical yield.

Learn more about percent yield at: brainly.com/question/8638404

#SPJ1

4 0
1 year ago
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