Step-by-step answer:
Given:
mean, mu = 200 m
standard deviation, sigma = 30 m
sample size, N = 5
Maximum deviation for no damage, D = 100 m
Solution:
Z-score for maximum deviation
= (D-mu)/sigma
= (100-200)/30
= -10/3
From normal distribution tables, the probability of right tail with
Z= - 10/3
is 0.9995709, which represents the probability that the parachute will open at 100m or more.
Thus, by the multiplication rule, the probability that all five parachutes will ALL open at 100m or more is the product of the individual probabilities, i.e.
P(all five safe) = 0.9995709^5 = 0.9978565
So there is an approximately 1-0.9978565 = 0.214% probability that at least one of the five parachutes will open below 100m
Answer:
There should be a number of 14 students in each row
Step-by-step explanation:
Find the factors of 196 then find the Greatest factor pairs which give you the numbers of 14 and 14. Now you have your answer of 14 rows and 14 columns.
Answer:
So the answer is 108.75
Step-by-step explanation:
15 * $4.25 = 63.75
12* $3.75 = 45
63.75 + 45 = 108.75.
Answer:108.75
For this case we have the following inequality:
3y - 2x> 8
The first thing we should do is to graph the function.
Then, see the set of points that are the solution of the inequality.
The solution set is given by the shaded region.
See attached image.
Answer:
Shaded region.
See attached image.
It is positive.
Hope this helped.