Answer:
,,,,,, ,,,,,,,, ,,,,,,,,,,,,
Step-by-step explanation:
,,,,,,,,,! ....,,,,, ..,,,.,,,,,. .......? ........!
.... .... ....!
Area = 32m^2q
Area = bh
Area = 8mq · 4m
Given that,
KM bisects ∠LKJ.
m∠LKM = 4x + 12 and m∠MKJ = 6x - 6
To find,
The value of x.
Solution,
As KM bisects ∠LKJ. It would mean that,
m∠LKM = m∠MKJ
Putting the above values,
4x+12=6x-6
We can solve the above equations as follows :
4x-6x=-12-6
-2x=-18
x=9
Therefore, the value of x is equal to 9.
x = -2
y = 5
Given two equations
1. 7x + 10y = 36
2. y = 2x + 9
Substitute 2x + 9 for y in equation 1.
We have
7x + 10y = 36
7x + 10(2x + 9) = 36
Distribute 10 into (2x + 9)
7x + 10 x 2x + 10 x 9 = 36
7x + 20x + 90 = 36
27x + 90 = 36
Subtract 90 from both sides to eliminate 90 on the left side
27x + 90 - 90 = 36 - 90
27x = -54
Divide both sides by 27 to isolate x
27x/27 = -54/27
Now substitute -2 into either equation to get y
Using equation 2, we have
y = 2x + 9
= 2 x -2 + 9
= -4 + 9
= 5
Check
7(-2) + 10(5) = 36
Given
Required
Determine CD
Since, C is a point on BD, the relationship between the given parameters is;
Substitute the values of BD, BC and CD
Collect Like Terms
Divide both sides by -4
To determine the length of CD;
Substitute 3 for x in
Hence;