, , , , , , ,, , ,, , , , , ,, , ,,,

In triangle ABC below, line segment AB is 9 meters long and like segment BC is 7 meters long. use the Pythagorean theorem to fin

Cloud [144]

I have the answer attached.

3 0

4 years ago

Read 2 more answers

The average yearly earnings of male college graduates(with at least a bachelor's degree) are $59500 for men aged 25 to 34. The a

Goshia [24]

Answer:

Step-by-step explanation:

The question is incomplete. The complete question is:

The average yearly earnings of male college graduates (with at least a bachelor's degree) are $58,000 for men aged 25 to 34. The average yearly earnings of female college graduates with the same qualifications are $49,339. based on the results below, can it be concluded that there is a difference in mean earnings between male and female college graduates? Use the 0.01 level of significance.

sample mean: men $59,235 women $52,487

population standard deviation: men 8,945 women 10,125

sample size: men 40 women 35

a. state hypothesis

b. find the critical value(s)

c. compute the test value

d. make the decision

e. summarize the results

Solution:

This is a test of 2 independent groups. The population standard deviations are not known. Let μ1 be the mean yearly earnings of male college graduates and μ2 be the mean yearly earnings of female college graduates.

The random variable is μ1 - μ2 = difference in the mean average earnings between male and female graduates.

a) We would set up the hypothesis.

The null hypothesis is

H0 : μ1 = μ2 H0 : μ1 - μ2 = 0

The alternative hypothesis is

H1 : μ1 ≠ μ2 H1 : μ1 - μ2 ≠ 0

This is a two tailed test.

b) Since sample standard deviation is known, we would determine the test statistic by using the t test. The formula is

(x1 - x2)/√(s1²/n1 + s2²/n2)

From the information given,

x1 = 59235

x2 = 59487

s1 = 8945

s2 = 10125

n1 = 40

n2 = 35

t = (59235 - 59487)/√(8945²/40 + 10125²/35)

t = - 0.11

The formula for determining the degree of freedom is

df = [s1²/n1 + s2²/n2]²/(1/n1 - 1)(s1²/n1)² + (1/n2 - 1)(s2²/n2)²

df = [8945²/40 + 10125²/35]²/[(1/40 - 1)(8945²/40)² + (1/35 - 1)(10125²/35)²] = 24298427164944.27/354925314702.92865

df = 68

c) We would determine the probability value from the t test calculator. It becomes

p value = 0.91

d) Since alpha, 0.1 > than the p value, 0.91, then we would fail to reject the null hypothesis.

e) We can conclude that at 10% level of significance, there is no difference in mean earnings between male and female college graduates.

5 0

3 years ago

Challenge Question for Fun - Solve the problem: 66 x 200 = ?

Likurg_2 [28]

<span>13200 is the answer for the question </span>

5 0

4 years ago

Read 2 more answers

Kelsie works at a bicycle shop as a salesperson. She records the number of bicycles she sells daily. Here is the probability dis

Andru [333]

Answer:

a) $E(B)= \sum_{i=1}^n B_i P(B_i) =0*0.3+1*0.5+2*0.15+ 3*0.05=0.95$

b) $E(T)= \sum_{i=1}^n T_i P(T_i) =10*0.3+20*0.5+30*0.15+ 40*0.05=19.5$

c) $E(B^2)= \sum_{i=1}^n B^2_i P(B_i) =0^2 *0.3+1^2 *0.5+2^2 *0.15+ 3^2 *0.05=1.55$

And the variance is given by:

$Var(B) = E(B^2) -[E(B)]^2 = 1.55- [0.95]^2 =0.6475$

And the deviation would be $Sd(B) = \sqrt{0.6475}=0.8047$

$E(T^2)= \sum_{i=1}^n T^2_i P(T_i) =10^2 *0.3+20^2 *0.5+30^2 *0.15+ 40^2 *0.05=445$

And the variance is given by:

$Var(T) = E(T^2) -[E(T)]^2 = 445- [19.5]^2 =64.75$

And the deviation would be $Sd(T) = \sqrt{64.75}=8.047$

Step-by-step explanation:

Previous concepts

In statistics and probability analysis, the expected value "is calculated by multiplying each of the possible outcomes by the likelihood each outcome will occur and then summing all of those values".

The variance of a random variable Var(X) is the expected value of the squared deviation from the mean of X, E(X).

And the standard deviation of a random variable X is just the square root of the variance.

Solution to the problem

Part a

For this case we have the following info:

B 0 1 2 3

____________________________________

T 10 20 30 40

____________________________________

P 0.3 0.5 0.15 0.05

____________________________________

And we can calculate the expected value for the random variable B like this:

$E(B)= \sum_{i=1}^n B_i P(B_i) =0*0.3+1*0.5+2*0.15+ 3*0.05=0.95$

Part b

Similar to part a we can find the expected value for the random variable T like this:

$E(T)= \sum_{i=1}^n T_i P(T_i) =10*0.3+20*0.5+30*0.15+ 40*0.05=19.5$

Part c

In order to find the variance for B we need to calculate the second moment given by:

$E(B^2)= \sum_{i=1}^n B^2_i P(B_i) =0^2 *0.3+1^2 *0.5+2^2 *0.15+ 3^2 *0.05=1.55$

And the variance is given by:

$Var(B) = E(B^2) -[E(B)]^2 = 1.55- [0.95]^2 =0.6475$

And the deviation would be $Sd(B) = \sqrt{0.6475}=0.8047$

Similar for the random variable T we have:

$E(T^2)= \sum_{i=1}^n T^2_i P(T_i) =10^2 *0.3+20^2 *0.5+30^2 *0.15+ 40^2 *0.05=445$

And the variance is given by:

$Var(T) = E(T^2) -[E(T)]^2 = 445- [19.5]^2 =64.75$

And the deviation would be $Sd(B) = \sqrt{64.75}=8.047$

7 0

4 years ago

WHO EVER AWNSERS FIRST AND MAKES THE AWNSER CORRECT ILL MARK BRAINLIEST

Vladimir [108]

Spinning 7- 1/8 chance
Spinning not 7- 7/8 chance
Spinning an even number- 4/8
Spinning a number less than 5- 4/8

Thus, the event that has the greatest likelihood is "Spinning not 7"

5 0

3 years ago