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marta [7]
3 years ago
5

PLEASE HELP; WILL GIVE BRAINLIEST - GEOMETRY

Mathematics
1 answer:
Ede4ka [16]3 years ago
4 0
If you are trying to simplify 36(pi)/4, then 9(pi) would be what you want because it is the simplest form of that fraction. It also depends on the answer choices. Sometimes they want simplest form and other times they’ll have you leave the fraction as is. Typically simplifying completely is your best bet though.

Hope this helps!
You might be interested in
I need the work shown not just the answers please
Yuliya22 [10]
1.) To find the surface area, we want to find the area of each side, then add them all up together:
Area of base=lwA=(5)(5)A=25 cm²
Area of triangle=1/2bhA=(1/2)(5)(12.5)A=31.25 cm²
Since the 4 triangles have the same area, we can multiply the area we found by 4 and then add the area of the square:
SA=(4)(31.25) + 25SA=125+25SA=150 cm²

2.) <span>To find the volume use the formula: 

V=(1/3)lwh
V=(1/3)(5)(5)(12.5)
V=104.167 cm^3</span>
3 0
3 years ago
What is <br> - 3/4 x ( -12 ) <br> please i need this by today
S_A_V [24]
-12 x -12 = 144 I’m pretty sure if not then it is something different
3 0
3 years ago
What percent of 16 is 0.12?
valentinak56 [21]

Answer:

0.75%

Step-by-step explanation:

Convert the fractions and then multiply by 100.

5 0
3 years ago
Read 2 more answers
F (x)=5x+1 9(x)=-2x+15
german

Answer:

x = 0

Step-by-step explanation:

(x)=5x+19(x)=-2x+15

We move all terms to the left:

(x)-(5x+19(x))=0

We add all the numbers together, and all the variables

x-(+24x)=0

We get rid of parentheses

x-24x=0

We add all the numbers together, and all the variables

-23x=0

x=0/-23

x=0

4 0
3 years ago
If a=2b^3 and b= -1/2c ^-2,express a in terms of c.
ElenaW [278]

Answer:

Part 1) a=-\frac{1}{4c^6}

Part 2) a=-\frac{1}{4c^{-6}}

Step-by-step explanation:

Part 1) we have

a=2b^{3} ----> equation A

b=-\frac{1}{2}c^{-2} ----> equation B

substitute equation B in equation A

a=2(-\frac{1}{2}c^{-2})^{3}

Applying property of exponents

(x^{m})^{n}=x^{m*n}

x^{-m} =\frac{1}{x^{m}}

a=2(-\frac{1}{2}c^{-2})^{3}=2(-\frac{1}{2})^3(c^{-2})^{3}=2(-\frac{1}{8})(c^{-6})=-\frac{1}{4c^6}

therefore

a=-\frac{1}{4c^6}

Part 2) we have

a=2b^{3} ----> equation A

b=-\frac{1}{2c^{-2}}=-\frac{c^{2}}{2} ----> equation B

substitute equation B in equation A

a=2(-\frac{c^{2}}{2})^{3}

Applying property of exponents

(x^{m})^{n}=x^{m*n}

x^{-m} =\frac{1}{x^{m}}

a=2(-\frac{c^{2}}{2})^{3}=2(-\frac{c^{6}}{8})

simplify

a=-\frac{c^{6}}{4}

therefore

a=-\frac{1}{4c^{-6}}

6 0
3 years ago
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