The car will take 300 m before it stops due to applying break.
<h3>What's the relation between initial velocity, final velocity, acceleration and distance?</h3>
- As per Newton's equation of motion, V² - U² = 2aS
- V= final velocity velocity of the object, U = initial velocity velocity of the object, a= acceleration, S = distance covered by the object
- Here, U = 60 ft/sec, V = 0 m/s, a= -6 ft/sec²
- So, 0² - 60² = 2×6× S
=> -3600 = -12S
=> S = 3600/12 = 300 m
Thus, we can conclude that the distance covered by the car is 300 m before it stopped.
Disclaimer: The question was given incomplete on the portal. Here is the complete question.
Question: A car is being driven at a rate of 60 ft/sec when the brakes are applied. The car decelerates at a constant rate of 6 ft/sec². How long will it take before the car stops?
Learn more about the Newton's equation of motion here:
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Answer:
F = 35651 [N]
Explanation:
To solve this problem we must use Newton's second law, which tells us that the sum of forces is equal to the product of mass by acceleration.
But first, we must use the following equation of kinematics to find acceleration.
where:
Vf = final velocity = 185 [m/s]
Vi = initial velocity = 0 (the cannon ball is at rest in the first moment)
a = acceleration [m/s²]
x = distance = 3.6 [m]
Now replacing these values into the equation:
(185)² = 0² + (2*a*3.6)
34225 = 7.2*a
a = 34225/7.2
a = 4753.5 [m/s²]
Now using Newton's second law we have:
F = m*a
where:
F = force [N]
m = mass = 7.5 [kg]
F = 7.5*4753.5
F = 35651 [N]
OK.
You're sitting in a soft comfy chair, reading a book in your lap.
The book stays put, and you eventually start to get sleepy, because
there's almost no acceleration happening.
The chair you're sitting in is seat #27B in a huge jet taking you to visit
your grandparents who live a thousand miles away.
The airplane is maybe 7 miles up, passing over the ground at nearly
500 miles per hour, flying straight, level, and fast !
Answer:
Hope this helps if not so sorry ;-;
Explanation:
Work is done when a force that is applied to an object moves that object. The work is calculated by multiplying the force by the amount of movement of an object (W = F *
Note:
Have a nice day :)