10 parsecs<span>Another way to look at this is that the apparent magnitude (brightness from true distance) is brighter than the absolute magnitude (brightness from 10 parsecsaway). So Ross 128 must be closer than 10 parsecs, making star look brighter than it "really" is.</span>
Answer:
A tuner is a subsystem that receives radio frequency (RF) transmissions and converts the selected carrier frequency and its associated bandwidth into a fixed frequency that is suitable for further processing, usually because a lower frequency is used on the output.
hope it helps ya mate.
Answer:
F = 268 Hz
Explanation:
The beat frequency is given as:
|
So, for the first flute and tuning fork:
where,
F = Frequency of tuning fork
F = 248 Hz ± 20 Hz
F = 268 Hz (OR) 228 Hz
Now, for the second flute and tuning fork:
where,
F = Frequency of tuning fork
F = 288 Hz ± 20 Hz
F = 268 Hz (OR) 308 Hz
Since, 268 Hz is common from both calculations. Therefore, it will be the frequency of the tuning fork.
<u>F = 268 Hz</u>
W = fd Divide both sides by d
= f Switch the sides to make it easier to read
f =
w = fd Divide both sides by f
= d Switch the sides to make it easier to read
d =