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natta225 [31]
3 years ago
12

a custodian pulls a vacuum 13.5 m with a 33.9 N force at a 55 degree angle, against a 14.1 N friction force. Find the work done

by the custodian.
Physics
1 answer:
pshichka [43]3 years ago
5 0

Answer:

The answer is 190.35

Explanation:

Given values be put in the formula that is

W=F×D

W=14.1×13.5

W=190.35

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You would also have to eat right lol
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how does spatial pattern of heights illustrate the relationship between temperature density and the rate of vertical pressure ch
Anika [276]

The rate of change of vertical pressure is directly proportional to density and also directly proportional to temperature.

Generally, the relationship between temperature, density and rate of vertical pressure is given as;

\rho = \frac{PM}{RT}

\frac{dP}{dz} = -\rho g\\\\

where;

  • <em>ρ is density</em>
  • <em>T is temperature</em>
  • <em>dP is rate of change of vertical  pressure</em>

Thus, from the formula above, we can conclude the following relationship between temperature, density and the rate of vertical pressure change in spatial pattern of heights.

The rate of change of vertical pressure is directly proportional to density and also directly proportional to temperature.

Learn  more here:brainly.com/question/25395377

5 0
3 years ago
Sound travels through water at a speed of 1500 m/s. If the frequency of a sound is 1000 Hz, what is the wavelength?
ratelena [41]

Answer:

1.5m

Explanation:

Velocity=1500m/s

Frequency=1000hz

Wavelength =velocity ➗ frequency

wavelength =1500 ➗ 1000

Wavelength=1.5m

3 0
3 years ago
State the principle of floatation​
WARRIOR [948]

Explanation:

<em><u>Principle of Floatation</u></em>

Principle of Floatation states that weight of floating body is equal to weight of water displaced by it

7 0
3 years ago
A car tire rotates with an average angular speed of 32 rad/s. In what time interval will the tire rotate 3.5 times? Answer in un
stiks02 [169]

Answer:

\Delta t = 0.687\ s

Explanation:

given,

Angular speed of the tire = 32 rad/s

Displacement of the wheel = 3.5 rev

Δ θ = 3.5 x 2 π

        = 7 π rad

now,

Time interval of the car to rotate 7π rad

using equation

\omega_{avg} =\dfrac{\Delta \theta}{\Delta t}

\Delta t=\dfrac{7\pi}{32}

\Delta t = 0.687\ s

Time taken to rotate 3.5 times is equal to 0.687 s.

3 0
3 years ago
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