A rocket ship carrying passengers blasts off to go from New York to Hong Kong, a distance of about 13,000 km. (a) How fast (in t
erms of c) must the rocket ship go to have its own length shortened by 1%? c (b) Ignore effects of general relativity and determine how much time (in s) the rocket ship's clock and the ground-based clocks differ when the rocket ship arrives in Hong Kong.
1 answer:
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By equation of motion we have v = u + at
Where u = Initial velocity, v = final velocity, t = time taken and a = acceleration
Here v = 141 m/s, u = 17.7 m/s and t = 6 s
On substitution we will get
141 = 17.7+ 6a
So, a = (141-17.7)/6 = 20. 55 m/
Aceeleration = 20. 55 m/ along north direction.
Answer:
mass = 0.18 [kg]
Explanation:
This is a classic problem where we can apply the definition of density which is equal to mass over volume.
mass = 0.18*1
mass = 0.18 [kg]