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kicyunya [14]
3 years ago
10

A rocket ship carrying passengers blasts off to go from New York to Hong Kong, a distance of about 13,000 km. (a) How fast (in t

erms of c) must the rocket ship go to have its own length shortened by 1%? c (b) Ignore effects of general relativity and determine how much time (in s) the rocket ship's clock and the ground-based clocks differ when the rocket ship arrives in Hong Kong.

Physics
1 answer:
lapo4ka [179]3 years ago
8 0

Answer:

0.14c

0.003 s

Explanation:

See attachment

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: The truck is to be towed using two ropes. Determine the magnitudes of forces FA and FB acting on each rope in order to develop
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Answer:

Fa=774 N

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Explanation:

We will solve this problem by equating forces on each axis.

  1. On x-axis let forces in positive x-direction be positive and forces in negative x-direction be negative
  2. On y-axis let forces in positive y-direction be positive and forces in negative y-direction be negative

While towing we know that car is mot moving in y-direction so net force in y-axis must be zero

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⇒Fa*sin(50)-Fb*sin(20)=0

⇒Fa*sin(50)=Fb*sin(20)

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⇒∑Fx=950  

⇒Fa*cos(20)+Fb*cos(50)=950

⇒2.24*Fb*cos(20)+Fb(50)=950

⇒Fb*(2.24*cos(20)+cos(50))=950

⇒Fb=\frac{950}{2.24*cos(20)+cos(50)}

⇒Fb=\frac{950}{2.24*0.94+0.64}

⇒ Fb=\frac{950}{2.75}=345.5

⇒Fa=2.24*Fb

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      =773.93

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