<u>Step-by-step explanation:</u>
A good example that comes to find is the fuel gauge found on a car, this gauge allows the driver to monitor the percentage of fuel left in the car.
Let's assume the car fuel tank has a capacity of 100 liters. if the indicator is showing half-filled, to illustrate this in percentage it is written as 50% while decimal it will be 0.5.
Answer:
(-1)/28
Step-by-step explanation:
Simplify the following:
((-19)/2×1/38)/7
(-19)/2×1/38 = (-19)/(2×38):
((-19)/(2×38))/7
(-19)/(2×38)×1/7 = (-19)/(2×38×7):
(-19)/(2×38×7)
The gcd of -19 and 38 is 19, so (-19)/(2×38×7) = (19 (-1))/(2 (19×2) 7) = 19/19×(-1)/(2×2×7) = (-1)/(2×2×7):
(-1)/(2×2×7)
2×2 = 4:
(-1)/(4×7)
4×7 = 28:
Answer: (-1)/28
Answer:
Ruby
Step-by-step explanation:
why because this is more chances then the other one
Answer:
This is a typical radioactive decay problem which uses the general form:
A = A0e^(-kt)
So, in the given equation, A0 = 192 and k = 0.015. We are to find the amount of substance left after t = 55 years. That would be represented by A. The solution is as follows:
A = 192e^(-0.015*55)
A = 84 mg
2 out of 10 chances
2/10 is 1/5