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Stolb23 [73]
3 years ago
13

A 40-meter-long blade of a wind turbine makes one complete revolution in 10 seconds. To the nearest tenth, the linear velocity o

f the blade is ____meters per second.

Mathematics
2 answers:
Pani-rosa [81]3 years ago
7 0
The distance the tip travels is
  2π·(40 m) = 80π m

Then its speed is
  (80π m)/(10 s) = 8π m/2 ≈ 25.1 m/s
aliya0001 [1]3 years ago
4 0

Answer:

The answer is 25.1 m/s

Step-by-step explanation:

In order to determine the linear velocity of the blade, we have to know about circles.

In any circle, the expression of its perimeter is:

P=2\pi R

Where:

P=Perimeter of the circle

R=Radius of the circle.

To determine the linear velocity, first we have to determine the perimeter that the long blade describes.

The long blade lengths 40 meters. This value represents the radius of the circle movement. Then the perimeter is:

R=40\\P=2\pi (40)\\P=80\pi

Then, the linear velocity is the rate of the perimeter per one complete revolution:

V=\frac{P}{T}=\frac{80\pi }{10}=8*3.142=25.136

We have to round the final value to the nearest tenth. I have attached an image that shows the position of the nearest tenth.

Finally, the linear velocity is 25.1 m/s.

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The mean number of words per minute (WPM) read by sixth graders is 86 with a variance of 225. If 44 sixth graders are randomly s
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P(X<=x) = 1 + 5.486 = 6.486

The z-score of the information given is,

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Where,

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From the information given,

x = 3.71

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σ  = √225 = 15

hence,

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thus,

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3 0
2 years ago
Romb ma obwód równy 32 cm. Jakie jest pole tego rombu, jeżeli jego wysokość ma 3 cm?
Goshia [24]

Answer:

24 cm²

Step-by-step explanation:

Z zadanego powyżej pytania uzyskano następujące dane:

Obwód (obwód) = 32 cm

Wysokość (h) = 3 cm

Obszar rombu (A) =?

Następnie określimy długość boku rombu. Można to uzyskać w następujący sposób:

Obwód, czyli obwód (P) = 32 cm

Strona (y) =?

P = 4 s

32 = 4 s

Podziel obie strony przez 4

s = 32/4

s = 8 cm

Stąd długość boku rombu wynosi 8 cm

Na koniec określimy obszar rombu w następujący sposób:

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A = 8 × 3

A = 24 cm²

Dlatego obszar rombu jest

24 cm².

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