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Degger [83]
2 years ago
13

The average commute to work (one way) is 25 minutes according to the 2005 American Community Survey. If we assume that commuting

times are normally distributed and that the standard deviation is 6.1 minutes, calculate the probability that a randomly selected commuter spends for the following cases.
1. More than 31 minutes commuting one way.
2. Less than 8 minutes commuting one way.
Mathematics
1 answer:
Stolb23 [73]2 years ago
7 0

Answer:

1. 0.1635

2. 0.0026

Step-by-step explanation:

The computation of the probability in the following cases are as follows:

1.

Given that

Mean = 25 minutes

ANd, the standard deviation is 6.1 minutes

So here the z score would be

= (31 - 25) ÷(6.1)

= 0.98

Now the probability is

= P(Z>0.98)

= 0.1635

2. the z score would be

= (8 - 25) ÷(6.1)

= -2.79

Now the probability is

= P(Z<-2.79)

= 0.0026

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Daniel [21]

Answer:

Step-by-step explanation:

As the statement is ‘‘if and only if’’ we need to prove two implications

  1. f : X \rightarrow Y is surjective implies there exists a function h : Y \rightarrow X such that  f\circ h = 1_Y.
  2. If there exists a function h : Y \rightarrow X such that  f\circ h = 1_Y, then f : X \rightarrow Y is surjective

Let us start by the first implication.

Our hypothesis is that the function f : X \rightarrow Y is surjective. From this we know that for every y\in Y there exist, at least, one x\in X such that y=f(x).

Now, define the sets X_y = \{x\in X: y=f(x)\}. Notice that the set X_y is the pre-image of the element y. Also, from the fact that f is a function we deduce that X_{y_1}\cap X_{y_2}=\emptyset, and because  f the sets X_y are no empty.

From each set X_y  choose only one element x_y, and notice that f(x_y)=y.

So, we can define the function h:Y\rightarrow X as h(y)=x_y. It is no difficult to conclude that f\circ h(y) = f(x_y)=y. With this we have that f\circ h=1_Y, and the prove is complete.

Now, let us prove the second implication.

We have that there exists a function  h:Y\rightarrow X  such that f\circ h=1_Y.

Take an element y\in Y, then f\circ h(y)=y. Now, write x=h(y) and notice that x\in X. Also, with this we have that f(x)=y.

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A(n - 3) +8= bn for n please help me
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Given equation: A(n - 3) +8= bn.

Solution: On the left side of the equation we have A(n-3).

We don't have any sign in between A and parenthesis (n-3).

So, we need to multiply A and (n-3).

We need to apply distributive property to multiply A and (n-3).

Distributing A over (n-3), we get

A(n-3) = A*n - 3*A = An -3A.

Substituting this value in original equation,

An -3A +8= bn.

We need to solve it for n, so we get n terms on a side.

We have An on left side, we need to get rid n from left side.

Subtracting An from both sides, we get

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Factoring out n on right side from bn-an.

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Dividing both sides by (b-A),

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\frac{(-3A+8)}{(b-A)} =n   Final answer.

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