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Volgvan
3 years ago
11

Help on this please on 16

Mathematics
1 answer:
timama [110]3 years ago
8 0

Answer:

Step-by-step explanation:B

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23/6

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If X &gt; 0 and y &gt; 0 , then which quadrant holds the solutions ?
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First Quadrant

Step-by-step explanation:

The quadrant in which both x and y are greater than 0 is the First Quadrant.

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Kelvin ordered four pizzas for a birthday party. The pizzas were cut into eighths. How many slices were there? (Draw a picture t
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A consulting firm has received 2 Super Bowl playoff tickets from one of its clients. To be fair, the firm is randomly selecting
Soloha48 [4]

Answer:

Therefore the only statement that is not true is b.)

Step-by-step explanation:

There employees are 6 secretaries, 5 consultants and 4 partners in the firm.

a.) The probability that a secretary wins in the first draw

= \frac{number \hspace{0.1cm} of \hspace{0.1cm} secreataries}{total \hspace{0.1cm} number \hspace{0.1cm} of \hspace{0.1cm} employees}  = \frac{6}{15}

b.) The probability that a secretary wins a ticket on second draw.  It has been given that a ticket was won on the first draw by a consultant.

p(secretary wins on second draw | consultant  wins on first draw)

=\frac{p((consultant \hspace{0.1cm} wins \hspace{0.1cm} on \hspace{0.1cm} first \hspace{0.1cm}draw)\cap( secretary\hspace{0.1cm} wins\hspace{0.1cm} on second \hspace{0.1cm}draw))}{p(consultant \hspace{0.1cm} wins \hspace{0.1cm} on \hspace{0.1cm} first \hspace{0.1cm}draw)}

= \frac{\frac{5}{15}  \times \frac{6}{14}}{\frac{5}{15} }  = \frac{6}{14}  .

The probability that  a ticket was won on the first draw by a consultant a secretary wins a ticket on second draw  = \frac{6}{15} is not true.

The probability that a secretary wins on the second draw  = \frac{number \hspace{0.1cm} of  \hspace{0.1cm} secretaries  \hspace{0.1cm} remaining } { number  \hspace{0.1cm} of  \hspace{0.1cm} employees  \hspace{0.1cm} remaining}  = \frac{6 - 1}{15 - 1}  = \frac{5}{14}

c.) The probability that a consultant wins on the first draw  =

\frac{number \hspace{0.1cm} of  \hspace{0.1cm} consultants  \hspace{0.1cm}  } { number  \hspace{0.1cm} of  \hspace{0.1cm} employees  \hspace{0.1cm} }  = \frac{5 }{15}  = \frac{1}{3}

d.) The probability of two secretaries winning both tickets

= (probability of a secretary winning in the first draw) × (The probability that a secretary wins on the second draw)

= \frac{6}{15}  \times \frac{5}{14}  = \frac{1}{7}

Therefore the only statement that is not true is b.)

5 0
3 years ago
Consider a 25 factorial design. (a) How many factors and levels are considered in this factorial experiment
Bad White [126]

Answer:

Step-by-step explanation:

From the information given;

We are to take a look at a 2⁵ factorial design.

The factorial design consists of carrying out the design of equipment by testing it by modifying not the parameters one by one but by modifying several simultaneous parameters.

An experiment is termed to be a 2⁵ factorial experiment if in the experiment 5 factors are studied consecutively with each at two-level.

Thus, there are five factors and 2 levels in the experiment.

8 0
3 years ago
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