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2 years ago

PLZZZZZZZ NEED HELP!!!!!!

Mathematics

1 answer:

kakasveta [241]2 years ago

8 0

Answer:

I don't really get the question, but i'd pick 0.09, or -1. Is that k12?

I recognize it because that looks like a quiz and i'm in k12.

Step-by-step explanation:

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Solving one-step inequalities by multiplying/dividing<br><img src="https://tex.z-dn.net/?f=14v%20%5Cleqslant%2014" id="TexFormul

liubo4ka [24]

Answer: v <= 1

Step-by-step explanation:

When you have a variable by a number, you do the opposite of multiplying, so you divide

Since there's only 14v you divide 14 from itself leaving just the variable

14 ÷ 14 = 1

You repeat this and divide on the other side

14 ÷ 14 = 1

Since you arent dividing by a negative on both sides, the arrow stays the same

v <= 1

Hope this helps!

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3 years ago

How do I find the average rate of change?

Alenkasestr [34]

Answer:

add them all up together and then divide by the number of items

Step-by-step explanation:

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3 years ago

1. Consider the data set 1,2,3,4,5,6,7,8,9.

ivanzaharov [21]

Answer: a) Mean = 5, Median = 5

b) Mean = 15, Median = 5

c) Due to presence of outlier i.e. 99.

Step-by-step explanation:

Since we have given that

1,2,3,4,5,6,7,8,9

Here, n = 9 which is odd

So, Mean would be

$\dfrac{1+2+3+4+5+6+7+8+9}{9}=\dfrac{45}{9}=5$

Median = $(\dfrac{n+1}{2})^{th}=\dfrac{9+1}{2}=5^{th}=5$

If 9 is replaced by 99,

1,2,3,4,5,6,7,8,99

So, mean would be

$\dfrac{1+2+3+4+5+6+7+8+99}{9}=\dfrac{135}{9}=15$

Median would be same as before i.e. 5

The mean is neither central nor typical for the data due to outlier i.e. 99

Hence, a) Mean = 5, Median = 5

b) Mean = 15, Median = 5

c) Due to presence of outlier i.e. 99.

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3 years ago

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nika2105 [10]

Answer: 7 miles, (I'm pretty sure)

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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3 years ago