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ipn [44]
3 years ago
5

1 3/5+8 1/2 find the sum I don’t need steps

Mathematics
1 answer:
jekas [21]3 years ago
5 0
The Answer is 10 1/10
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Nancy borrows $5000 at a rate of 16% interest per year. What is the amount due at the of 5 hears if the interest is compunded co
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The amount due in 5 years is 11,000
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If there are 600 marbles in a jar, and 22% of them are red, how many are red
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Answer:

132

Step-by-step explanation:

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3 years ago
Gideon is painting all sides of a square pyramid-shaped decoration at the top of his fence post. A net of the decoration is show
frez [133]
Gideon is painting all sides thus we find the overall area of the square pyramid given in the picture. A square pyramid is a polyhedron that consists of a square and 4 triangles. To solve the area that Gideon will have to paint, we can calculate the area of the square and the area of the triangles then add these two values of area. We proceed as follows:
Area of the square = s^2 where s is the measure of the side
Area of the square = 4^2 = 16 in^2

Area of the triangle= 1/2 bh where b is the base of the triangle and h is height of the triangle
Area of the triangle = 1/2 (4) (5) = 10 in^2
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Total area of the triangles = 4 x 10 = 40 in^2

We then add the two areas,
Total Area = 16 + 40 = 56 in^2

Thus the total area that Gideon will have to paint for one square pyramid is 56 in^2.
6 0
3 years ago
Triangle J K L is shown. Angle J K L is 120 degrees and angle K L J is 40 degrees. The length of K L is 2 and the length of J L
Veseljchak [2.6K]

Answer:

k \approx 5$ units

Step-by-step explanation:

In Triangle JKL

\angle K=120^\circ\\\angle L=40^\circ\\KL=2\\JL=k

We want to determine the approximate value of k using the law of sines.

\angle J+\angle K+\angle L=180^\circ $ (Sum of angles in a \triangle)\\\angle J+120^\circ+40^\circ=180^\circ \\\angle J=180^\circ-(120^\circ+40^\circ)=20^\circ

Using Law of Sines

\dfrac{k}{\sin K} =\dfrac{j}{\sin J} \\\dfrac{k}{\sin 120} =\dfrac{2}{\sin 20} \\k=\sin 120 \times \dfrac{2}{\sin 20}\\k=5.06\\k \approx 5$ units

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3 years ago
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lyudmila [28]
If the number of pages assigned is divisible by both 12 and 2, then we can conclude that the minimum number of pages assigned cannot be less that 12 since any number less than 12 is not divisible by 12.

The answer is 12.
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