Answer:
It isn't possible.
Step-by-step explanation:
Let G be a graph with n vertices. There are n possible degrees: 0,1,...,n-1.
Observe that a graph can not contain a vertice with degree n-1 and a vertice with degree 0 because if one of the vertices has degree n-1 means that this vertice is adjacent to all others vertices, then the other vertices has at least degree 1.
Then there are n vertices and n-1 possible degrees. By the pigeon principle there are two vertices that have the same degree.
Step-by-step explanation:
The expressions are not properly written
Given
RS = 4x – 9
ST = 19
RT = 8x – 14
Based on the given parameters, the addition postulate below is true
RS+ST = RT
Substitute
4x-9+19 = 8x-14
collect like terms
4x-8x = -14-19+9
-4x = -33+9
-4x = -24
x = -24/-4
x = 6
Get RS:
RS = 4x-9
RS = 4(6)- 9
RS = 24-9
RS = 15
Get RT:
RT = 8x - 14
RT = 8(6)-14
RT = 48-14
RT = 34
The answer is 0.5 metres.
4/2 = 1/2
1/2 100cm is 50cm
50cm = 0.5 metres.
Hello from MrBillDoesMath!
Answer: A, C, D
Discussion:
The solution of the quadratic equation ax^2 + bx + c = 0 is
x = ( -b +\- (b^2 - 4ac) ^ (1/2) ) /2a
The expression b^2 - 4ac is called the discriminant, occurs in the numerator of the solution, and also occurs inside a square root (called a radicand).
The question, while intelligible, should be stated more clearly.
Regards, MrB