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DanielleElmas [232]
3 years ago
9

Which sequence matches the recursive formula?

Mathematics
2 answers:
Ostrovityanka [42]3 years ago
8 0
A1 = 2
a2 = (a1)^2 + 3 = 2^2 + 3 = 4 + 3 = 7
a3 = (a2)^2 + 3 = 7^2 + 3 = 49 + 3 = 52
a4 = (a3)^2 + 3 = 52^2 + 3 = 2,704 + 3 = 2,707

Option C is the correct answer.
marshall27 [118]3 years ago
8 0

Answer:

The solution is 2, 7, 52, 2707, .... To find each term in the sequence, you square the previous term and add 3. This sequence is represented by the recursive formula an = (an-1)2 + 3, where a1 = 2.

So It's C.

Step-by-step explanation:

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If a line contains the point (0, -1) and has a slope of 2, then which of the following points also lies on the line?
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(1,1)

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A motorcycle cost $12,000 when it was purchased. The value of a motorcycle decreases by 6% each year. Find the rate of decay eac
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<span>the rate of decay each month can calculated using the following formula:
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</span><span>So the 0.5% is the right answer.
I hope it helped.</span>
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The difference between two numbers is 10 and their sum is 20. Find the biggest number.
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15

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x + y = 20

substitute for x:

10 + y + y = 20

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If X²⁰¹³ + 1/X²⁰¹³ = 2, then find the value of X²⁰²² + 1/X²⁰²² = ?​
enyata [817]

Step-by-step explanation:

\bf➤ \underline{Given-} \\

\sf{x^{2013} + \frac{1}{x^{2013}} = 2}\\

\bf➤ \underline{To\: find-} \\

\sf {the\: value \: of \: x^{2022} + \frac{1}{x^{2022}}= ?}\\

\bf ➤\underline{Solution-} \\

<u>Let us assume that:</u>

\rm: \longmapsto u =  {x}^{2013}

<u>Therefore, the equation becomes:</u>

\rm: \longmapsto u +  \dfrac{1}{u}  = 2

\rm: \longmapsto \dfrac{  {u}^{2} + 1}{u}  = 2

\rm: \longmapsto{u}^{2} + 1 = 2u

\rm: \longmapsto{u}^{2} - 2u + 1 =0

\rm: \longmapsto  {(u - 1)}^{2} =0

\rm: \longmapsto u = 1

<u>Now substitute the value of u. We get:</u>

\rm: \longmapsto {x}^{2013}  = 1

\rm: \longmapsto x = 1

<u>Therefore:</u>

\rm: \longmapsto {x}^{2022}  +  \dfrac{1}{ {x}^{2022} }  = 1 + 1

\rm: \longmapsto {x}^{2022}  +  \dfrac{1}{ {x}^{2022} }  = 2

★ <u>Which is our required answer.</u>

\textsf{\large{\underline{More To Know}:}}

(a + b)² = a² + 2ab + b²

(a - b)² = a² - 2ab + b²

a² - b² = (a + b)(a - b)

(a + b)³ = a³ + 3ab(a + b) + b³

(a - b)³ = a³ - 3ab(a - b) - b³

a³ + b³ = (a + b)(a² - ab + b²)

a³ - b³ = (a - b)(a² + ab + b²)

(x + a)(x + b) = x² + (a + b)x + ab

(x + a)(x - b) = x² + (a - b)x - ab

(x - a)(x + b) = x² - (a - b)x - ab

(x - a)(x - b) = x² - (a + b)x + ab

6 0
3 years ago
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