Answer: 0.0035
Step-by-step explanation:
Given : The readings on thermometers are normally distributed with a mean of 0 degrees C and a standard deviation of 1.00 degrees C.
i.e. 
and 
Let x denotes the readings on thermometers.
Then, the probability that a randomly selected thermometer reads greater than 2.17 will be :_
![P(X>2.7)=1-P(\xleq2.7)\\\\=1-P(\dfrac{x-\mu}{\sigma}\leq\dfrac{2.7-0}{1})\\\\=1-P(z\leq2.7)\ \ [\because\ z=\dfrac{x-\mu}{\sigma}]\\\\=1-0.9965\ \ [\text{By z-table}]\ \\\\=0.0035](https://tex.z-dn.net/?f=P%28X%3E2.7%29%3D1-P%28%5Cxleq2.7%29%5C%5C%5C%5C%3D1-P%28%5Cdfrac%7Bx-%5Cmu%7D%7B%5Csigma%7D%5Cleq%5Cdfrac%7B2.7-0%7D%7B1%7D%29%5C%5C%5C%5C%3D1-P%28z%5Cleq2.7%29%5C%20%5C%20%5B%5Cbecause%5C%20z%3D%5Cdfrac%7Bx-%5Cmu%7D%7B%5Csigma%7D%5D%5C%5C%5C%5C%3D1-0.9965%5C%20%5C%20%5B%5Ctext%7BBy%20z-table%7D%5D%5C%20%5C%5C%5C%5C%3D0.0035)
Hence, the probability that a randomly selected thermometer reads greater than 2.17 = 0.0035
The required region is attached below .
Answer:
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- <u><em>Option A. 94</em></u>
Explanation:
The column of digits to the left (before the vertical line) contains the largest place-value digits.
Here is how you read the values:
- Third row: 80, 80, 81, 82, 85, 88, 89
Thus, the highest score received is 94.
Answer:
12
Step-by-step explanation:
1.08 1.08 divded by 0.09 equals 12
Answer:
Confidence Interval = (23.776, 24.224)
Step-by-step explanation:
Restaurant chain claims that its bottles of ketchup contain 24 ounces of ketchup on average.
⇒ Mean = 24 ounces.
Standard Deviation = 0.8
Number of bottles used for sample = 49
⇒ n = 49
Confidence level = 95%
Corresponding z value with 95% confidence level = 1.96
Now, confidence interval is given by the following expression :
Hence, Confidence Interval = (23.776, 24.224)
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