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sergiy2304 [10]
4 years ago
13

Write two equivalent expressions involving decimals that illustrate the distributive property

Mathematics
1 answer:
Ilya [14]4 years ago
5 0
Distributive Property of each given equation:
<span>96 divided by 6 
</span>       => 2(40 + 8) / 6
       => (80) + (16) / 6
       => 96 / 6
       => 16

<span>85 divided by 5
</span>        =>(2(30 + 15) - 5 )/ 5
        => ((60 + 30) - 5) / 5
        => (90 - 5 ) / 5
        => 85 / 5
        => 17

<span>85 divided by 6
</span>        =>(2(30 + 15) - 5 )/ 6
        => ((60 + 30) - 5) / 6
        => (90 - 5 ) / 6
        => 85 / 6
        => 14.166…

<span>168 divided by 7
</span>        =>3(50 + 6) / 7
        => (150 + 18) / 7
        => (168 ) / 7
        => 24

<span>104 divided by 4
</span>        =>2(50 + 2) / 4
        => (100 + 4) / 4
        => 104 / 4
<span>        => 26        </span>

<span>171 divided by 9
=> 3 (50 + 7) / 9
   => (150 + 21) / 9
   => (171) / 9
   => 19
</span>
<span>102 divided by 9
   => 2 (50 + 1) / 9
   => ((2 x 50) + (2 x 1)) / 9
   => (100 + 2 ) / 9
   => 102 / 9
   =>  11.333……
</span>
<span>102 divided by 6
   => 2 (50 + 1 ) / 6
   => ((2 x 50) + (2 x 1)) / 6
   => (100 + 2) / 6
   => 102 / 6
   => 17
</span>
210 divided by 5
   => 2 (100 + 5) / 5
   => ( (2 x 100) + (2 x 5) ) /5
<span>   => (200 + 10)  / 5 </span>
   => 210 /5
<span>   => 42
</span>
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Are they Equivalent why or why not?
Olin [163]
They are equivalent because when you distribute the -0.5 into 3x+5 you get the expression -1.5x+2.5
7 0
3 years ago
| 5t-1 |=6 <br><br> Show all work
kipiarov [429]

Answer:

t = 1.4

Step-by-step explanation:

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5 0
3 years ago
Read 2 more answers
A college entrance exam company determined that a score of 24 on the mathematics portion of the exam suggests that a student is
seraphim [82]

Answer:

a) The Z -value 2.397 < 2.576 at 99% or 0.01% level of significance

Null hypothesis is accepted at  0.01% level of significance

<em>They score is above 24 on the math portion of the​ exam</em>

<em>b) </em>

<u><em>Null Hypothesis</em></u>: There is no significance difference between the college level mathematics and math courses in high school

H₀: μ = 24

<u>Alternative Hypothesis: </u>H₁: μ ≠ 24

<u>Step-by-step explanation:</u>

<u><em>Step(i)</em></u>:-

Given random sample 'n' = 250

Given data sample mean x⁻ = 24.5

Standard deviation = 3.3

<u><em>Null Hypothesis</em></u>: There is no significance difference between the college level mathematics and math courses in high school

H₀: μ = 24

<u>Alternative Hypothesis: </u>H₁: μ ≠ 24

test statistic

Z = \frac{x^{-} - mean}{\frac{S.D}{\sqrt{n} } }

Z = \frac{24.5 - 24}{\frac{3.3}{\sqrt{250} } } = \frac{0.5}{0.2087} = 2.397

a) 99% or 0.01% level of significance

Level of significance ∝ = 0.01

Z_{\frac{\alpha }{2} } = Z_{\frac{0.01}{2} } = Z_{0.005} =2.576

The Z -value 2.397 < 2.576 at 99% or 0.01% level of significance

Null hypothesis is accepted at  0.01% level of significance

<em>They score is above 24 on the math portion of the​ exam</em>

b) 95% or 0.05% level of significance

Level of significance ∝ = 0.05

Z_{\frac{\alpha }{2} } = Z_{\frac{0.05}{2} } = Z_{0.025} = 1.96

The Z -value 2.397 > 1.96 at 95% or 0.05% level of significance

Null hypothesis is Rejected at  0.05% level of significance

<em>They score is below 24 on the math portion of the​ exam</em>

6 0
3 years ago
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