Question

Simplify the expression (3x^2)^4y^2x^-2/x^-3y^5

Answer 1

we are given

$\frac{(3x^2)^4y^2x^{-2}}{(x^{-3}y^5)}$

$\frac{3^4x^8y^2x^{-2}}{x^{-3}y^5}$

we can make exponent positive

$=\frac{3^4x^8y^2x^{-2}*x^3}{y^5}$

$=81x^{9}y^{-3}$..............Answer