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3 years ago

PLEASE ANSWER ASAPFind the value of x in each case:

Mathematics

1 answer:

Triss [41]3 years ago

3 0

158+ 148+ 32 + x = 360
x= 22

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8.5 x $99.99 =<br> $849.92<br> O $91.49<br> O $108.49<br> O $11.76<br><br> help

kolbaska11 [484]

Answer:

O $849,915

Step-by-step explanation:

$8.5 \times 99.99$

$= 849.915$

3 0

3 years ago

Question 8. PV = nRT, solve for T please?<br><br>Question 10. C= Wtc÷1000, solve for W, please?

sp2606 [1]

Answers:

$\huge \boxed{T= \frac{P V}{n R} } \\ \\ \\ \\ \huge \boxed{W= \displaystyle \frac{1000C }{tc}}$

$\rule[225]{225}{2}$

Step-by-step explanation:

$P \cdot V = n \cdot R \cdot T$

Dividing both sides by n · R:

$\displaystyle \frac{P \cdot V}{n \cdot R} =T$

$\displaystyle C=\frac{Wtc }{1000}$

Multiplying both sides by 1000:

$1000C=Wtc$

Dividing both sides by tc:

$\displaystyle \frac{1000C }{tc}=W$

<h2 />

$\rule[225]{225}{2}$

4 0

3 years ago

4x + y=22<br> y=x-3<br> Need fast help plz

Flura [38]

Answer:

x=5

Step-by-step explanation:

4x+(x-3)=22

5x-3=22

+3 +3

5x=25

/5 /5

x=5

8 0

3 years ago

If you have 9 quaters AND 21 pennies, in percents, WHAT is THE chance THAT you WILL pick a penny OUT is a hat?

nadezda [96]

We know that you have 9 quarters

We also know that you have 21 pennies

Probability is represented as "determined factor" / total

First, we need to find the total amount of possibilities. This means that you have to add 21 and 9

21 + 9 = 30

We want to know the probability of picking a penny out of the hat, so you would represent this as:

21/30

To turn it into a percent, divide 21 by 30.

21 ÷ 30 = 0.7

0.7 is equivalent to 70% as a percent

This means that you will have a 70% chance of picking a penny out

Answer: 70%

4 0

3 years ago

Which classification best describes the following system of equations?

wolverine [178]

The given system of equations is consistent and independent so, $\fbox{\begin\\\ \bf option (3)\\\end{minispace}}$ is correct.

Further explanation:

A system of equations is said to be a consistent system if the solution exists and if the solution does not exist then it is an inconsistent system.

If a consistent system has a unique solution then it is an independent system of equations but if the number of solutions is infinite then it is a dependent system of equations.

Label the given equations as shown below:

$\boxed{x-2y+4z=3}$ …… (1)

$\boxed{12x+5y-3z=36}$ …… (2)

$\boxed{9x-10y+5z=27}$ …… (3)

The augmented matrix for the above equations is, as follows:

$\left[\begin{array}{ccc}1&-2&4\\12&5&-3\\9&-10&5\end{array}\Biggm\vert\begin{array}{c}3\\26\\27\end{array}\right]$

Apply row transformation $R_{2}\rightarrow R_{2}-12R_{1}$ and $R_{3}\rightarrow R_{3}-9R_{1}$ as,

$\left[\begin{array}{ccc}1&-2&4\\0&29&-51\\0&8&-31\end{array}\Biggm\vert\begin{array}{c}3\\0\\0\end{array}\right]$

Now, apply row transformation $R_{2}\rightarrow R_{2}-4R_{3}$ and $R_{3}\rightarrow R_{3}-3R_{2}$ as,

$\left[\begin{array}{ccc}1&-2&4\\0&-3&73\\0&-1&188\end{array}\Biggm\vert\begin{array}{c}3\\0\\0\end{array}\right]$

Now, apply row transformations $R_{2}\rightarrow -R_{2}+2R_{3}$ and $R_{3}\rightarrow R_{3}+R_{2}$ as,

$\left[\begin{array}{ccc}1&-2&4\\0&1&303\\0&0&491\end{array}\Biggm\vert\begin{array}{c}3\\0\\0\end{array}\right]$

The equations obtained from the above augmented matrix are,

$\begin{aligned}x-2y+4z&=3\\y+303z&=0\\491z&=0\end{aligned}$

The first equation is simplified to obtain the value of z as,

$\begin{aligned}491z&=0\\z&=0\end{aligned}$

Substitute $0$ for $z$ in the equation $y+303z=0$ to obtain the value of $y$ as,

$\begin{aligned}y+(303\cdot0)&=0\\y&=0\end{aligned}$

Now, substitute $0$ for $z$ and $0$ for $y$ in the equation $x-2y+4z=3$ to obtain the value of $x$ as,

$\begin{aligned}x-(2\cdot0)+(4\cdot0)&=3\\x&=3\end{aligned}$

Therefore, the value of $x$ is $3$ , the value of $y$ is $0$ and the value of $z$ is $0$ and the system has a unique solution.

Thus, the given system of equations is consistent and independent.

Option (1)

Here, the first option is inconsistent and dependent.

There exists a solution of the given system of equations so it is consistent.

Therefore, option (1) is incorrect.

Option (2)

Here, the second option is consistent and dependent.

There exists a solution of the given system of equations so it is consistent.

Also, the solution is unique therefore the system of equations is independent.

Therefore, option (2) is incorrect.

Option (3)

Here, the third option is consistent and independent.

There exists a solution of the given system of equations so it is consistent.

Also, the solution is unique therefore the system of equations is independent.

Therefore, option (3) is correct.

Option (4)

Here, the fourth option is inconsistent and independent.

There exists a solution of the given system of equations so it is consistent.

Therefore, option (4) is incorrect.

Learn more:

1. A problem on circle brainly.com/question/9510228.

2. A problem on general equation of a circle brainly.com/question/1506955.

Answer details

Grade: High school

Subject: Mathematics

Chapter: System of linear equations

Keywords: Equations, unique solution, independent, dependent, consistent, inconsistent, infinite solutions, homogeneous equation, non- homogeneous equation, determinant.

5 0

3 years ago

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