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3 years ago

A rectangle's length is twice its width. if the perimeter is 66 cm find the width of the rectangle

1 answer:

6 0

Perimeter = 2L + 2W

Let x = width and let 2x = length

Perimeter = 66

2x + 2(2x) = 66

2x + 4x = 66 --> 6x = 66 --> x = 66/6 --> x = 11

The width of the rectangle is 11 cm.

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3 years ago

In a figure, OB is the radius of a big semicircle and XB is the radius of the small semicircle. Given that OX = 14 cm, Calculate

oee [108]

Answer:

perimeter of the shaded region = 88 +44+28 =160 cm

Step-by-step explanation:

perimeter of shaded region = length AO + arc OB + arc AB

length AO = radius of bigger circle

radius of bigger circle = OX + OB = 2×radius of smaller circle = 2×14 cm = 28 cm

therefore AO = 28 cm

length of arc oB= half of circumference of smaller circle = $\pi$ ×14 = 44 cm

length of arc ab = half of circumference of bigger circle = $\pi$ ×28 = $\frac{22}{7}$ ×28= 88

therefore perimeter of the shaded region = 88 +44+28 =160 cm

area of the shaded region = half of area of bigger circle - half of area of smaller circle

= $\frac{1}{2} \pi 28^{2} -\frac{1}{2} \pi 14^{2}$

= $\frac{\pi }{2} (28^{2} -14^{2} )$

solving we gen area of shaded region = 924

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just olya [345]

Answer:

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2 years ago