What is a question without an = sign called

Mathematics

2 answers:

daser333 [38]3 years ago

8 0

Answer:

A query

Step-by-step explanation:

Norma-Jean [14]3 years ago

4 0

Answer:

a question without an = sign is called an expression

Step-by-step explanation:

You might be interested in

Inverse laplace of [(1/s^2)-(48/s^5)]

Katen [24]

**Refresh page if you see [ tex ]**

I am not familiar with Laplace transforms, so my explanation probably won't help, but given that for two Laplace transform $F(s)$ and $G(s)$ , then $\mathcal{L}^{-1}\{aF(s)+bG(s)\} = a\mathcal{L}^{-1}\{F(s)\}+b\mathcal{L}^{-1}\{G(s)\}$

Given that $\dfrac{1}{s^2} = \dfrac{1!}{s^2}$ and $-\dfrac{48}{s^5} = -2\cdot\dfrac{4!}{s^5}$

So you have $\mathcal{L}^{-1}\left\{\dfrac{1}{s^2} - 2\cdot\dfrac{4!}{s^5}\right\} = \mathcal{L}^{-1}\left\{\dfrac{1}{s^2}\right\} - 2\mathcal{L}^{-1}\left\{\dfrac{4!}{s^5}\right\}$

From Table of Laplace Transform, you have $\mathcal{L}\{t^n\} = \dfrac{n!}{s^{n+1}}$ and hence $\mathcal{L}^{-1}\left\{\dfrac{n!}{s^{n+1}}\right\} = t^n$

So you have $\mathcal{L}^{-1}\left\{\dfrac{1}{s^2}\right\} - 2\mathcal{L}^{-1}\left\{\dfrac{4!}{s^5}\right\} = \boxed{t-2t^4}$ .

Hope this helps...

7 0

3 years ago

0.47=_ hundredths = _tenths and _ hundredths

Gennadij [26K]

7 hundredths 4 tenths

4 0

3 years ago

Read 2 more answers

isobel and marnie volunteer at a daycare center Isobel works 3 hours for every 2 hours marine works. if the two girls together w

Anon25 [30]

I=1.5m
m+1.5m=20
2.5m=20
m=8
20-8=12
Isobel worked 12 hours.

6 0