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nikitadnepr [17]
3 years ago
5

Write the equation of a line with slope 3 and y-intercept −3.

Mathematics
2 answers:
Aleks04 [339]3 years ago
5 0

y = 3x - 3

the equation of a line in slope-intercept form is

y = mx + c ( m is the slope and c the y-intercept )

here m = 3 and c = - 3, hence equation is

y = 3x - 3


natta225 [31]3 years ago
4 0
The equation would be y = 3x-3




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If f(x)=(x+3)³+4<br> let g(x)=f(x+1)-2<br> find when g(x)=12
lana [24]

Answer:

x=\sqrt[3]{10}-2

Step-by-step explanation:

The composite function (f(x+1)) is moved in the x-axis by -1, you know this by solving x+1=0.

The equivalent expresion for f(x+1) is

f(x+1)= (x-1+3)^{3}+4

f(x+1)=(x+2)^{3}+ 4

Eval the above expression in g(x)

g(x)=(x+2)^{3}+4-2

We must find x that gives g(x)=12

The equation is the following

12=(x+2)^{3}+2

Grouping terms>

(x+2)^{3} =10

To solve for x, must apply cubic root in both sides of equation:

\sqrt[3]{(x+2)^{3} } =\sqrt[3]{10}

it then turns in the following>

x+2=\sqrt[3]{10}\\

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