Answer:
1/sqrt10
Step-by-step explanation:
1) Find out cosA using formula (cosA)^2+(sinA)^2=1
The module of cosA= sqrt (1- (-3/5)^2)= sqrt 16/25=4/5
So cosA=-4/5 or cosA=4/5.
Due to the condition 270degrees< A<360 degrees, 0<cosA<1 that's why cosA=4/5.
2) Find sinA/2 using a formula cosA= 1-2sinA/2*sinA/2 where cosA=4/5.
(sinA/2)^2= 0.1
sinA= sqrt 0.1= 1/ sqrt10 or sinA= - sqrt 0.1= -1/sqrt10
But 270°< A< 360°, then 270/2°<A/2<360/2°
135°<A/2<180°, so sinA/2 must be positive and the only correct answer is
sin A/2= 1/sqrt10
Answer:
The larger of the two angles is x, which is 75. y is the smaller angle at 15.
Step-by-step explanation:
In order to find these, we can use our solved value for y in the second equation to plug into the first equation. This method is called substitution.
x + y = 90
x + (1/5x) = 90
1.2x = 90
x = 75
Now we can plug that value into either equation to find y
y = 1/5x
y = 1/5(75)
y = 15
Answer:
- 100
Step-by-step explanation:
OK open
The Pdf and look at the working
The answer is T
Hope this helps.
