Hello,
Let a the first, b the second and c the third.
a+b+c=53
b=a/3
c=2a
==>a+a/3+2a=53
==>10a/3=53
==>a=15.9
c=2*a=2*15.9=31.8
b=a/3=15.9/3=5.3
Proof: a+b+c=15.9+5.3+31.8=53
The second number is 5.3
Answer:

Step-by-step explanation:
Given
t = 2 to 7
Required
Find the average speed over these intervals
The function is not given; so, I'll represent the function as s(t)
When 

When 


This gives:


The first one is 810
The second is -120
Answer:
(3, -1)
Step-by-step explanation: