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Marina86 [1]
4 years ago
9

Which is greater 1/2 52%​

Mathematics
1 answer:
Trava [24]4 years ago
8 0

Answer:

52% because 1/2 equals to .5 and 52% equals to .52

Step-by-step explanation:

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What is the solution to the following equation 4(3x-6)+15=27
Svetlanka [38]

Answer:

x = 3

Step-by-step explanation:

4(3x - 6) + 15 = 27 \\ 12x - 24 + 15 = 27 \\ 12x - 24 = 27 - 15 \\ 12x - 24 =1 2 \\ 12x = 12 + 24 \\ 12x = 36 \\  \frac{12x}{12}  =  \frac{36}{12}  \\ x = 3

3 0
3 years ago
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5. If p-p-16 then 3p-7=​
Nataliya [291]
P= 16
3p-7
3(16)-7
48-7
41
7 0
3 years ago
A line has a slope of 1/7 and passes through the point (0, -2). What is its equation in
faltersainse [42]

Answer:

y=\frac{1}{7} x-2

Step-by-step explanation:

7 0
3 years ago
Please help with 1 and 2 :)
nordsb [41]

Answer:

1. The domain for the number of fruit cups is 0 minimum and 20 maximum.

   [0 < x < 20].

2. [10 < y < 70]

Step-by-step explanation:

1. The domain is 0 to 20 because there are 20 people total who will each have a fruit cup

2. The range is $10 to $70 because the minimum price is $10 without any fruit cups and $70 when there are 20 fruit cups.

4 0
3 years ago
PLEASE HELP ASAP! I don’t recall how to do this!
MakcuM [25]

Answer:

Step-by-step explanation:

For a. we start by dividing both sides by 200:

(1.05)^x=1.885

In order to solve for x, we have to get it out from its position of an exponent.  Do that by taking the natural log of both sides:

ln(1.05)^x=ln(1.885)

Applying the power rule for logs lets us now bring down the x in front of the ln:

x * ln(1.05) = ln(1.885)

Now we can divide both sides by ln(1.05) to solve for x:

x=\frac{ln(1.885)}{ln(1.05)}

Do this on your calculator to find that

x = 12.99294297

For b. we will first apply the rule for "undoing" the addition of logs by multipllying:

ln(x*x^2)=5

Simplifying gives you

ln(x^3)=5

Applying the power rule allows us to bring down the 3 in front of the ln:

3 * ln(x) = 5

Now we can divide both sides by 3 to get

ln(x)=\frac{5}{3}

Take the inverse ln by raising each side to e:

e^{ln(x)}=e^{\frac{5}{3}}

The "e" and the ln on the left undo each other, leaving you with just x; and raising e to the power or 5/3 gives you that

x = 5.29449005

For c. begin by dividing both sides by 20 to get:

\frac{1}{2}=e^{.1x}

"Undo" that e by taking the ln of both sides:

ln(.5)=ln(e^{.1x})

When the ln and the e undo each other on the right you're left with just .1x; on the left we have, from our calculators:

-.6931471806 = .1x

x = -6.931471806

Question d. is a bit more complicated than the others.  Begin by turning the base of 4 into a base of 2 so they are "like" in a sense:

(2^2)^x-6(2)^x=-8

Now we will bring over the -8 by adding:

(2^2)^x-6(2)^x+8=0

We can turn this into a quadratic of sorts and factor it, but we have to use a u substitution.  Let's let u=2^x

When we do that, we can rewrite the polynomial as

u^2-6u+8=0

This factors very nicely into u = 4 and u = 2

But don't forget the substitution that we made earlier to make this easy to factor.  Now we have to put it back in:

2^x=4,2^x=2

For the first solution, we will change the base of 4 into a 2 again like we did in the beginning:

2^2=2^x

Now that the bases are the same, we can say that

x = 2

For the second solution, we will raise the 2 on the right to a power of 1 to get:

2^x=2^1

Now that the bases are the same, we can say that

x = 1

5 0
3 years ago
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