All categories

3 years ago

Write improper fraction as a mixed number 85/40

Mathematics

2 answers:

VLD [36.1K]3 years ago

6 0

Regular is 2 and 5/40
Simplified is 2 and 1/8

maks197457 [2]3 years ago

4 0

85 ÷ 40 = 2 with remainder 5

so... the divisor 40 will be our denominator, the whole number we get is 2 and the remainder will be our numerator.

$2 \frac{5}{40}$

simplify...

2x 1/8

You might be interested in

Find the solution set. The solution set for 5v2 – 125 = 0 is?

Blababa [14]

The correct answer is. v=25/2

4 0

3 years ago

Read 2 more answers

Can someone help with my homework?

USPshnik [31]

Step-by-step explanation:

To divide by a fraction, multiply by its reciprocal.

1) (m² / 9) / (n² / m)

(m² / 9) × (m / n²)

m³ / (9n²)

2) (4 / y) / (2 / (yx))

(4 / y) × (yx / 2)

3) (x² / y) / (1 / y)

(x² / y) × (y / 1)

x²

4) (3 / b) / (9 / a²)

(3 / b) × (a² / 9)

a² / (3b)

5) (x² / 16) / (16 / y²)

(x² / 16) × (y² / 16)

x²y² / 256

5 0

3 years ago

How to do this question plz answer me step by step plzz plz

Iteru [2.4K]

Answer:

£13496.80

Step-by-step explanation:

We can ignore the £ sign for now, that is just units.

If we decrease a number by 4.5%, we will have to find $100-4.5=95.5$ % of 14132.77.

We can easily do this by setting up a proportion.

$\frac{x}{14132.77} = \frac{95.5}{100}$

Multiply 14132.77 by 95.5:

$14132.77\cdot95.5=1349679.535$

Divide by 100:

$1349679.535\div100=13496.79535$

Rounding this to two decimal places, it simplifies to 13496.80.

Hope this helped!

4 0

3 years ago

If water and oil are combined in a container, the resulting liquid is a(n)

Misha Larkins [42]

If water and oil are combined in a container, the resulting liquid is C.emulsion.

4 0

3 years ago

Suppose that the probabilities of a customer purchasing 0, 1, or 2 books at a book store are 0.20.2, 0.30.3, and 0.50.5, res

PIT_PIT [208]

Answer:

0.78

Step-by-step explanation:

We have the next probability distribution:

X P(X)

0 0.2

1 0.3

2 0.5

As we can see when we add all the probabilites the result is 1. Now calculating the mean we have:

$mean=\mu=(0\times0.2)+(1\times 0.3)+(2\times 0.5)=0+0.3+1=1.3$

The standard deviation is:

$\sigma=\sqrt{\sum(x-\mu)^{2}(P(x))}$

Then using the data that we have:

$\sigma=\sqrt{\sum(x-\mu)^{2}(P(x))}\\\sigma=\sqrt{(0-1.3)^{2}(0.2)+(1-1.3)^{2}(0.3)+(2-1.3)^{2}(0.5)}\\\\\sigma=\sqrt{(-1.3)^{2}(0.2)+(-0.3)^{2}(0.3)+(0.7)^{2}(0.5)}\\\\\sigma=\sqrt{(1.69)(0.2)+(0.09)(0.3)+(0.49)(0.5)}\\\\\sigma=\sqrt{0.338+0.027+0.245}\\\\\sigma=\sqrt{0.61}\\\\\sigma=0.78\\$

Then the standard deviation is 0.78

6 0

2 years ago