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3 years ago

Max has $2000: $1000 decreased in value exponentially at a rate of 0.5% annually

Mathematics

1 answer:

Sergio039 [100]3 years ago

6 0

Answer:

$2147.36

Step-by-step explanation:

The first value can be modeled by ...

b1 = 1000·(1 -0.005)^t

After 10 years, that balance is ...

b1 = 1000·0.995^10 = 951.11

The second value can be modeled by ...

b2 = 1000·(1 +0.018/2)^(2t)

After 10 years, that balance is ...

b2 = 1000·1.009^20 = 1196.25

The total of the two investments after 10 years is ...

$951.11 +1196.25 = $2147.36

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A football team played 90 matches. They won 37 matches.

Mekhanik [1.2K]

Answer: 44 matches

Step-by-step explanation:

Let's take the given information

They won 37 matches

1/9th of their matches resulted in a draw

1/9 out of 90 is 9

You can take 90/9 and you will get 9

Now let us add 37+9 and you get 47

Now take 90-47

44 Matches lost

22/45 or 44/90

5 0

3 years ago

What pair of points have a slope of -3/5

sergey [27]

Answer:

(5,0) and (0,3) have a slope of -3/5

Step-by-step explanation:

Here, we want to state a pair of points that have a slope of -3/5

Mathematically, we can have the slope of a straight line calculated as;

m = y2-y1/(x2-x1)

This could give points like (5,0) and (0,3)

3 0

3 years ago

#9. Find the slope of the line in the graph.

jekas [21]

The answer to this problem is -2/2

7 0

3 years ago

Find the equivalent fraction for 10/20

dezoksy [38]

$\frac{10}{20} = \frac{ \frac{10}{10} }{ \frac{20}{10} } = \frac{1}{2}$

6 0

3 years ago

(2pm^-1q^0)^-4 • 2m ^-1 p^3 / 2pq^2

Montano1993 [528]

Answer:

$\dfrac{m^3}{16p^2q^2}$

Step-by-step explanation:

Given:

$(2pm^{-1}q^0)^{-4}\cdot \dfrac{ 2m^{-1} p^3}{2pq^2}$

$m^{-1}=\dfrac{1}{m}$

$q^0=1$

$2pm^{-1}q^0=2p\cdot \dfrac{1}{m}\cdot 1=\dfrac{2p}{m}$

$(2pm^{-1}q^0)^{-4}=\left(\dfrac{2p}{m}\right)^{-4}=\left(\dfrac{m}{2p}\right)^4=\dfrac{m^4}{(2p)^4}=\dfrac{m^4}{16p^4}$

$m^{-1}=\dfrac{1}{m}$

$2m^{-1} p^3=2\cdot \dfrac{1}{m}\cdot p^3=\dfrac{2p^3}{m}$

$\dfrac{ 2m^{-1} p^3}{2pq^2}=\dfrac{\frac{2p^3}{m}}{2pq^2}=\dfrac{2p^3}{m}\cdot \dfrac{1}{2pq^2}=\dfrac{p^2}{mq^2}$

$(2pm^{-1}q^0)^{-4}\cdot \dfrac{ 2m^{-1} p^3}{2pq^2}=\dfrac{m^4}{16p^4}\cdot \dfrac{p^2}{mq^2}=\dfrac{m^3}{16p^2q^2}$

8 0

3 years ago