F(x) = - |x| +4 Define the key features of the graph to the provided absolute value function
1 answer:
Answer:
1. The minus before the |x| reflects the function in the x-axis. So it will still be V-shaped but instead but refected in the x-axis.
2. The +4 moves the function vertically 4 units upwards.
Step-by-step explanation:
We are given the function f(x) = - |x| +4. We know that the function f(x) = |x| only has positive values, so when x>0 the function is a straight line as in the function f(x) = x. When x<0 the function is also positive, as in the function f(x) = -x. So the graph is V-shaped with the vertex at the origin.
The f(x) = - |x| +4 has two important caracteristics:
1. The minus before the |x| reflects the function in the x-axis. So it will still be V-shaped but instead but refected in the x-axis.
2. The +4 moves the function vertically 4 units upwards.
So the graph of f(x) = - |x| +4 will be V-shaped, reflected in the x-axis and moved 4 units upwards.
Attached you can find the graph
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Answer:
1π
Step-by-step explanation:
suppose the radius of semicircle P is r,
then the radius of semicircle Q = (r+d)/2 ... d≤r
radius of semicircle R = (r-d)/2
area P = 1/2 (r)²π
area Q = 1/2 ((r+d)/2)² π = 1/8 (r² + 2rd + d²)π
area R = 1/2 ((r-d)/2)² π = 1/8 (r² - 2rd + d²)π
shaded area = P-Q-R = 1/2 r²π - 1/4 (r² + d²)π
= ((r² - d²)/4) * π
because there is no constant r value in the question and d value changes with the r change, when the vertical segment length equal the semicircle P radius (r), r=2 and d = 0
therefore the shaded area = ((2² -0²)/4)*π = 1π
