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Tems11 [23]
3 years ago
13

How many significant figures does 0.0102 have?

Mathematics
1 answer:
kakasveta [241]3 years ago
5 0
1. Non-zero digits are significant
2. Zeroes between two significant numbers are significant
3. Trailing zeroes are significant

0.0102 has 3 <span>significant figures
1 and 2 are non-zero digits (Rule 1)
0 between 1 and 2 is zero between </span>two significant numbers (Rule 2)
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Drag each tile to the correct box
ValentinkaMS [17]

Answer:

Arranging the solutions from the least to the highest;

1.         1.743 x 10⁻²

2.        3.626 x 10⁻²

3.        4.64 x 10⁻²

4.        3.162 x 10²

5.        4.214 x 10³

Step-by-step explanation:

The solutions of the mathematical expression are calculated as follows;

1. \ \ (4.3\times 10^6)(9.8\times 10^{-4}) = (4.3\times 9.8\times 10^{6-4}) = (42.14\times 10^2)= 4.214 \times 10^3

2. \ \ (2.9\times 10^7)(1.6\times 10^{-9}) = (2.9\times 1.6\times 10^{7-9}) = 4.64\times 10^{-2}

3. \ \ \frac{(4.7 \times 10^3)(8.6\times 10^{-7})}{(3.8\times 10^{-4})(6.1 \times 10^2)} = \frac{(4.7\times 8.6\times 10^{3-7})}{(3.8\times 6.1\times 10^{-4+2})} = \frac{4.042 \times 10^{-3}}{2.318\times 10^{-1}} = 1.743\times 10^{-2}

4. \ \ (4.9\times 10^3)(7.4\times 10^{-6}) = (4.9\times 7.4\times 10^{3-6}) = 3.626\times 10^{-2}

5. \ \ \frac{(3.9 \times 10^5)(8.7\times 10^{-3})}{(3.7\times 10^{-5})(2.9 \times 10^8)} = \frac{(3.9\times 8.7\times 10^{5-3})}{(3.7\times 2.9\times 10^{-4 +8 })} = \frac{3.393 \times 10^{-1}}{1.073\times 10^{-3}} = 3.162\times 10^{2}

Arranging the solutions from the least to the highest;

1.         1.743 x 10⁻²

2.        3.626 x 10⁻²

3.        4.64 x 10⁻²

4.        3.162 x 10²

5.        4.214 x 10³

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Shirley estimated the length of a board to be 18 inches. The actual length is 23 inches. To the nearest tenth of a percent, what
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The percent error of Shirley's estimate is 21.74%

<h3>Calculating pecent error</h3>

Given the following parameters

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