Factor 24 p + 64 Find "m" m+8=22

1 answer:

5 0

$24=8\cdot3;\ 64=8\cdot8\\\\24p+64=8\cdot3p+8\cdot8=\boxed{8(3p+8)}\\========================\\m+8=22\ \ \ |subtract\ 8\ from\ both\ sides\\\\m+8-8=22-8\\\\\boxed{m=14}$

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Which answers are equivalent to ? Choose all answers that are correct. A. 0.08 B. 8% C. 0.32 D. 32%

Llana [10]

A and B are equivalent and C and D are equivalent

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4 years ago

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Can anyone please help me answer the PICTURE IS PROVIDED!

Levart [38]

Answer:

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3 years ago

PRECAL Find the compliment of 0.25 Find the supplement of 7π/8

balandron [24]

The unit of measurement is not specified, so for the sake of this problem, we'll assume it's radians (If you need it in degrees, I'll be happy to edit).

Find the compliment of 0.25:

Complementary angles add up to 90 degrees. In radians, this would be π/2. If you're unsure how I got this, check degrees to radian conversions.

The compliment of 0.25 would be $\dfrac{\pi}{2} - \dfrac{1}{4}$ (1/4=0.25)

$\dfrac{\pi}{2} - \dfrac{1}{4}$

$= \dfrac{\pi}{2} - \dfrac{1}{4} = \dfrac{2\pi-1}{4}$

(This is the simplified form in case you're homework needs it in this form)

That's the compliment. In decimal (rounded to the nearest hundredth), this would be 1.32 radians.

Find the supplement of 7π/8:

Supplementary angles add up to 180 degrees. In radians, this would be π.

The supplement would be the following:

$\pi- \dfrac{7\pi}{8}$

$=\dfrac{8\pi}{8}-\dfrac{7\pi}{8}=\dfrac{\pi}{8}$

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Find the area of an isosceles trapezoid, if the lengths of its bases are 16 cm, and 30 cm, and the diagonals are perpendicular t

Klio2033 [76]

For this case we have:
a = 30 cm
c = 16 cm
We look for the length of the diagonal:
d = x + y
Where,
For x:
a ^ 2 = x ^ 2 + x ^ 2
x = a / root (2) = 30 / root (2) = 21.2132 cm
For y:
c ^ 2 = y ^ 2 + y ^ 2
y = c / root (2) = 16 / root (2) = 11.3137 cm
The diagonal is:
d = x + y
d = 21.2132 + 11.3137
d = 32.5269 cm
Then, the height is:
h = h1 + h2
For h1:
h1 = root (x ^ 2 - (a / 2) ^ 2) = root ((21.2132) ^ 2 - (30/2) ^ 2)
h1 = 15 cm
For h2:
h2 = root (y ^ 2 - (c / 2) ^ 2) = root ((11.3137) ^ 2 - (16/2) ^ 2)
h2 = 8 cm
Finally:
h = h1 + h2
h = 15 + 8
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Then, the area is:
A = (1/2) * (a + c) * (h)
A = (1/2) * (30 + 16) * (23)
A = 529 cm ^ 2
Answer:
the area of an isosceles trapezoid is:
A = 529 cm ^ 2

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