Question

On a coordinate plane, a line is drawn from point a to point b. point a is at (7, negative 2) and point b is at (negative 8, negative 9). what are the x- and y-coordinates of point c, which partitions the directed line segment from a to b into the ratio 5:8? round to the nearest tenth, if necessary. x = (startfraction m over m n endfraction) (x 2 minus x 1) x 1 y = (startfraction m over m n endfraction) (y 2 minus y 1) y 1 (–2.2, –6.3) (–2.4, –6.4) (2.7, –0.7) (1.2, –4.7)

Answer 1

The coordinate of the partition c on the line segment is (1.2, -4.7)

How to determine the coordinates of the partition?

The coordinates are given as:

A = (7,-2)

B = (-8,-9)

m:n = 5:8

The coordinate of the partition is calculated using:

$(x,y) = \frac{1}{m + n} * (mx_2 + nx_1, my_2 + ny_1)$

So, we have:

$(x,y) = \frac{1}{5 + 8} * (5 * -8 + 8 * 7, 5 * -9 + 8 * -2)$

Evaluate the sum and products

$(x,y) = \frac{1}{13} * (16, -61)$

Evaluate the product

(x,y) = (1.2, -4.7)

Hence, the coordinate of the partition on the line segment is (1.2, -4.7)

Read more about line segment ratios at:

brainly.com/question/12959377

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Answer 2

Answer:

(1.2, -4.7)

Step-by-step explanation:

Did on edge :)