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3 years ago

Which one is correct?

Mathematics

1 answer:

nordsb [41]3 years ago

6 0

Answer:

SSS or SAS

Step-by-step explanation:

Remark

Since the two diagonals bisect each other, you have created two sets of equal lines. If that is the case, then you could prove the equality of the triangles 2 different ways.

1) The angles at the center are vertically angles which makes them equal. Since they are equal, the triangles are congruent by SAS. Notice that the angle is between the 2 equal sides.

2) Since CD and AB are marked as being equal, the triangles are congurent by SSS.

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3.2x + 7.9 + 8.2 + 6.7x<br> Simplify the expressions. (not equations!) <br> Please help ASAP.

Temka [501]

Answer:

9.9x + 16.1

Step-by-step explanation:

SImplify using like terms

Simplify:

3.2x + 7.9 + 8.2 + 6.7x
3.2x + 6.7x + 7.9 + 8.2
9.9x + 16.1

-Chetan K

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2 years ago

Atreya runs 5 1/4 miles in 3/4 of an hour. If Atreyu continues at this rate, how far will he run in an hour?

kogti [31]

Answer: 63/16 = 3 1/16 or 7 if your divide it

Step-by-step explanation:

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2 years ago

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Which function below has the lowest y intercept? f(x) graph going through (0, 2) and (4, 0) g(x) Al had two dozen donuts when he

Shkiper50 [21]

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3 years ago

Two trains begin in Milford and end in Pinkerton, which is 300 miles away. Train A leaves Milford at 10:00 a.M. And travels at a

cluponka [151]

Answer:

B. Train B

Step-by-step explanation:

We are told that Milford and Pinkerton is 300 miles away.

Train A leaves Milford at 10:00 am. There are 3 hours between 10:00 am to 1:00 pm. So let us find distance traveled by train A in 3 hours.

$\text{Distance}=\text{Speed*Time}$

$\text{Distance traveled by train A}=90\frac{\text{ miles}}{\text{ hour}}\times 3\text{ hours}$

$\text{Distance traveled by train A}=90\times 3{\text{ miles}$

$\text{Distance traveled by train A}=270{\text{ miles}$

Since train A will cover 270 miles in 3 hours and distance between Milford and Pinkerton is 300 miles, therefore, train A will not arrive Pinkerton before 1:00 pm.

Since there are 5 hours between 8:00 am to 1:00 pm, so let us find distance traveled by train B in 5 hours.

$\text{Distance traveled by train B}=70\frac{\text{ miles}}{\text{ hour}}\times 5\text{ hours}$