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Nonamiya [84]
4 years ago
11

What are some of the basic things about domain and range functions I should know I have midterms this Monday

Mathematics
1 answer:
blagie [28]4 years ago
5 0

Answer:

Domain is all the possible x-values a function can have. For example, for the function f(x) = √x, the domain would be x ≥ 0, because you cannot square a negative number. Another example is the function g(x) = 2x. The domain of g(x) would be all real numbers, or ℝ.

Range is all possible y-values a function can have. For example, for the function f(x) = √x, the range would be f(x) ≥ 0, since the square root of a number will be positive. Another example is h(x) = x². The square of x will  not be negative, so the range of h(x) will be h(x) ≥ 0.

For functions of the parent family y = a(x - h)² + k, the domain and range will always be⇒ Domain: all real numbers, and Range: y ≥ k

For functions of the parent family y = a(x - h)³ + k, the domain and range will always be all real numbers.

For functions of the parent family y = a√(x - h) + k, the domain and range will always be⇒ Domain: x ≥ h, and Range: y ≥ k

For functions of the parent family y = a∛(x - h) + k, the domain and range will  always be all real numbers.

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A cable TV company charges a flat fee of $25 for basic cable service, plus
vovangra [49]

Answer:

8

Step-by-step explanation:

Each movie costs $4 since the bill increased by $4 when the customer watched a movie.

$29 - $25 = $4

Create an equality using this information.  Solve for x.

25 + 4x > 60

(25 + 4x) - 25 > (60) - 25

4x > 35

(4x)/4 > (35)/4

x > 8.75

Since the bill must stay under $60, round the answer down.  The customer can watch 8 movies with the given price range.

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3 years ago
82 children visit a sports centre.
igomit [66]

Answer:

4 adults are there to look out for the 12 kids and

and at least 2 adults are there to look out at the dancers

Step-by-step explanation:

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3 0
3 years ago
Let AB // ED , AB = 10 units, AC = 12 units, and DE = 5 units. What is the length of AD?​
zheka24 [161]

Answer:

length of CD = 18 units.

Step-by-step explanation:

In ΔABC and ΔCED,

AB║DE and AD is a transversal line,

m∠ABC = m∠CED [Alternate interior angles]

m∠ACB = m∠DCE [Vertically opposite angles]

ΔABC ~ ΔCED [By AA property of similarity]

Therefore, by the property of similar triangles, corresponding sides will be proportional.

\frac{AB}{DE}= \frac{AC}{DC}

\frac{10}{5}=\frac{12}{CD}

CD = 6

Since, AD = AC + CD

AD = 12 + 6

     = 18 units

Therefore, length of CD = 18 units.

4 0
3 years ago
Help!! i'll give brainliest
otez555 [7]

Answer:

Im pretty sure D

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
There are currently 16 teams in the National Football Conference (NFC). Of those teams, 11 have won at least one super bowl and
svp [43]

You are given 16 teams, 11 have won at least one super bowl and 5 have not.

A. The probability that both selected teams have won at least 1 super bowl is

Pr(A)=\dfrac{C_{11}^2}{C_{16}^2}=\dfrac{\dfrac{11!}{2!(11-2)!}}{\dfrac{16!}{2!(16-2)!}}=\dfrac{\dfrac{10\cdot 11}{2}}{\dfrac{15\cdot 16}{2}}=\dfrac{55}{120}=\dfrac{11}{24}.

B. The probability that neither selected team has won at least 1 super bowl is

Pr(B)=\dfrac{C_{5}^2}{C_{16}^2}=\dfrac{\dfrac{5!}{2!(5-2)!}}{\dfrac{16!}{2!(16-2)!}}=\dfrac{\dfrac{4\cdot 5}{2}}{\dfrac{15\cdot 16}{2}}=\dfrac{10}{120}=\dfrac{1}{12}.

C. The probability that at least one selected team has won at least 1 super bowl is

Pr(C)=1-Pr(B)=1-\dfrac{1}{12}=\dfrac{11}{12}.

D. to find the probability that the second team selected has won at least 1 super bowl given that the first team selected has not won a super bowl, consider such events:

P - the second team selected has won at least 1 super bowl;

Q - the first team selected has not won a super bowl.

Then

Pr(P|Q)=\dfrac{Pr(P\cap Q)}{Pr(Q)}=\dfrac{\dfrac{5\cdot 11}{C_{16}^2}}{\dfrac{C_5^1\cdot C_{15}^1}{C_{16}^2}}=\dfrac{55}{75}=\dfrac{11}{15}.

E. To find the probability that the second team selected has won at least 1 super bowl given that the first team selected has won at least 1 super bowl, consider events:

M - the second team selected has won at least 1 super bowl;

N - the first team selected has won at least 1 super bowl.

Then

Pr(M|N)=\dfrac{Pr(M\cap N)}{Pr(N)}=\dfrac{\dfrac{11\cdot 10}{C_{16}^2}}{\dfrac{C_{11}^1\cdot C_{15}^1}{C_{16}^2}}=\dfrac{110}{165}=\dfrac{2}{3}.

3 0
3 years ago
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